首页 \ 问答 \ 阻止哨兵发送消息(Stop sentry from sending messages)

阻止哨兵发送消息(Stop sentry from sending messages)

如果哨兵发送了大量类似的消息,有没有办法阻止它?

我们有很多客户,哨兵信息基本上都是一样的,所以哨兵骂我。


In case sentry sends lots of similar messages, is there a way to stop it?

We have a lot of clients and the sentry messages are basically all the same so sentry spams me.


原文:https://stackoverflow.com/questions/31423456
更新时间:2023-12-25 11:12

最满意答案

有两个问题:

  1. 您没有将您的功能传递给请求。 您正在将函数的返回值传递给请求。

  2. Request的回调函数必须具有签名(self,response)。

动态内容的解决方案如下: https//stackoverflow.com/a/24373576/2368836

它将消除将驱动程序传递给函数的需要。

因此,当你提出要求时,它应该是这样的......

scrapy.Request(urls, callback=self.parse_url)

如果你真的想用这个函数包含驱动程序,请阅读有关闭包的内容。

编辑:这是一个闭包解决方案,但我认为你应该使用我分享的链接,因为GHajba指出的原因。

   def parse_data(self, url_list, driver):
        def encapsulated(spider, response)
            data = get_data(driver.pagesource)
            .....
            .....
            yield item
    return encapsulated

然后你的请求看起来像

yield scrapy.request(url, callback=self.parse_data(url_list, driver)

There are two problems:

  1. You're not passing your function to the request. You are passing the return value of your function to the request.

  2. A callback function for Request must have the signature (self, response).

A solution to the dynamic content is here : https://stackoverflow.com/a/24373576/2368836

It will eliminate the need to pass the driver into the function.

So when yielding your request it should be like so...

scrapy.Request(urls, callback=self.parse_url)

If you really want to include the driver with that function read about closures.

Edit: Here is a closure solution but I think you should use the link I shared because of the reasons GHajba pointed out.

   def parse_data(self, url_list, driver):
        def encapsulated(spider, response)
            data = get_data(driver.pagesource)
            .....
            .....
            yield item
    return encapsulated

Then your request looks like

yield scrapy.request(url, callback=self.parse_data(url_list, driver)

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