WordPress发布查询(WordPress post query)
如果他们是第843页的孩子,我正试图显示带有“医疗”标签的帖子,到目前为止,我一切都在工作。 我需要在这个if语句中获取一些HTML,以便我可以将它全部包含在div中,并且还为列表设置一个开始和结束ul。
有人可以帮我解决这个最后一个驼峰吗? 我只是不确定在哪里添加HTML。
<?php if (843 == $post->post_parent) { global $post; $myposts = get_posts('numberposts=10&tag=medical&order=DESC'); foreach($myposts as $post) : ?> <li><a href="<?php the_permalink(); ?>"><?php the_title(); ?></a></li> <?php endforeach; } ?>
I am trying to show posts with the tag "medical" if they are a child of page 843, and so far, I have everything mostly working. I need to get some HTML within this if statement so that I can enclose it all in a div, and also to set an opening and closing ul for the list.
Can someone please help me get over this last hump? I'm just not sure where to add the HTML.
<?php if (843 == $post->post_parent) { global $post; $myposts = get_posts('numberposts=10&tag=medical&order=DESC'); foreach($myposts as $post) : ?> <li><a href="<?php the_permalink(); ?>"><?php the_title(); ?></a></li> <?php endforeach; } ?>
原文:https://stackoverflow.com/questions/9318941
最满意答案
Impala支持窗口功能。 这个问题是一个“缺口和孤岛”问题,因此可以使用行数的差异来解决:
select id, state, min(date) as start_date, max(date) as end_date from (select t.*, row_number() over (partition by id order by date) as seqnum_id, row_number() over (partition by id, state order by date) as seqnum_isd from table t ) t group by id, state, (seqnum_id - seqnum_isd);
差异的逻辑并不困难,但是当你第一次学习它时却很棘手。 它有助于运行子查询并查看行号值是什么 - 以及差异定义每个组的原因。
Impala supports window functions. This problem is a "gap-and-islands" problem, so it can be solved using a difference of row numbers:
select id, state, min(date) as start_date, max(date) as end_date from (select t.*, row_number() over (partition by id order by date) as seqnum_id, row_number() over (partition by id, state order by date) as seqnum_isd from table t ) t group by id, state, (seqnum_id - seqnum_isd);
The logic for the difference is not difficult, but tricky when you first learn it. It helps to run the subquery and see what the row number values are -- and why the difference defines each group.
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我不会在这里放置这个ID,因为我发现它在查询中无关紧要。 如果你希望你以后再说。 这是一个MSSQL查询。 select tb1.date as startdate,dateadd(d,-1,tb2.date) as enddate from the_table tb1 join the_table tb2 on tb2.date>tb1.date left join the_table tb3 on tb1.date
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