如何从当前时间到每天晚上10点30分（30分钟）获得时间间隔(How to get time interval for every 30:00(30 minutes) from current time to 10:30 pm)

 需要帮助来显示每30分钟的时间间隔，假设current time is 11:45 am 
 
 时间间隔应为： 12:00 pm,12:30 pm,01:00 pm,01:30 pm,02:00 pm,02:30 pm......10:30 pm. 
 
 NSString *time = @"10.30 pm";

     NSDate *date1;
        NSDate *date2;
        {
            NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
            [formatter setDateFormat:@"hh.mm a"];
            date1 = [formatter dateFromString:time];
            date2 = [formatter dateFromString:[formatter stringFromDate:[NSDate date]]];

        }
        NSTimeInterval interval = [date1 timeIntervalSinceDate: date2];//[date1 timeIntervalSince1970] - [date2 timeIntervalSince1970];
        int hour = interval / 3600;
        int minute = (int)interval % 3600 / 60;

        NSLog(@"%@ %dh %dm", interval<0?@"-":@"+", ABS(hour), ABS(minute));
 
 此代码返回当前时间和给定时间的差异，我如何进一步处理。 

Need help to show the time intervals for every 30 mins, suppose the current time is 11:45 am then
 
Time intervals should be : 12:00 pm,12:30 pm,01:00 pm,01:30 pm,02:00 pm,02:30 pm......10:30 pm.
 
 NSString *time = @"10.30 pm";

     NSDate *date1;
        NSDate *date2;
        {
            NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
            [formatter setDateFormat:@"hh.mm a"];
            date1 = [formatter dateFromString:time];
            date2 = [formatter dateFromString:[formatter stringFromDate:[NSDate date]]];

        }
        NSTimeInterval interval = [date1 timeIntervalSinceDate: date2];//[date1 timeIntervalSince1970] - [date2 timeIntervalSince1970];
        int hour = interval / 3600;
        int minute = (int)interval % 3600 / 60;

        NSLog(@"%@ %dh %dm", interval<0?@"-":@"+", ABS(hour), ABS(minute));
 
This code returns me difference of current time and the given time how can I proceed further. 

原文：https://stackoverflow.com/questions/37519033