在循环中选择具有相似模式的列名称(Selecting Column Name With Similar Pattern in a Loop)
我有一个oracle数据库表,其中包含field_name_1,field_name_2,...,field_name_200列。 我想为每行数据选择并更新循环中的每一列,请提供帮助。
DECLARE l_udf_vals tablea%ROWTYPE; field_val_temp varchar2(150); field_val field_val_temp%TYPE; BEGIN FOR yu IN (SELECT a.* FROM tablea a, tableb b, tablec c WHERE a.function_id=b.function_id AND b.col = c.col AND ) LOOP FOR i IN 1..200 LOOP field_val_temp := 'field_val_'||i; SELECT field_val_temp INTO field_val FROM tableb WHERE function_id='STDCUSAC' AND rec_key = yu.rec_key; IF field_val IS NOT NULL THEN UPDATE tablec SET 'field_val_'||i = field_val; END LOOP; COMMIT; END LOOP; COMMIT; END;
I have an oracle database table with columns field_name_1, field_name_2,..., field_name_200. I want to select and update each column in a loop for each row of data, kindly assist.
DECLARE l_udf_vals tablea%ROWTYPE; field_val_temp varchar2(150); field_val field_val_temp%TYPE; BEGIN FOR yu IN (SELECT a.* FROM tablea a, tableb b, tablec c WHERE a.function_id=b.function_id AND b.col = c.col AND ) LOOP FOR i IN 1..200 LOOP field_val_temp := 'field_val_'||i; SELECT field_val_temp INTO field_val FROM tableb WHERE function_id='STDCUSAC' AND rec_key = yu.rec_key; IF field_val IS NOT NULL THEN UPDATE tablec SET 'field_val_'||i = field_val; END LOOP; COMMIT; END LOOP; COMMIT; END;
原文:https://stackoverflow.com/questions/24244740
更新时间:2024-06-01 06:06
最满意答案
我能在这里找到答案: https : //stackoverflow.com/a/24017261/4762063
只有
Fragment
可见时,解决方法是有条件地膨胀Fragment
的菜单。I was able to find an answer here: https://stackoverflow.com/a/24017261/4762063
The work around is to conditionally inflate the
Fragment
's menu, only if theFragment
is visible.
相关问答
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有一个更简单,更简洁的方式来做到这一点。 IMO是的,但在这个阶段它需要大量的重写。 关于快速修复,从代码的外观来看,解决方案可能涉及此部分: try { fragment = (Fragment) fragmentClass.newInstance(); } catch (Exception e) { e.printStackTrace(); } FragmentManager = this.getSupportFragmentManager(); fragmentManag ...
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你可以使用菜单
在Android文档中搜索它。 然后根据需要setGroupVisible / enabled。 I was told the RemoveItem could cause problems, so I tried to avoid that. What I did was find the item and group ID from the items I didnt want to get removed, clear the list, and then ad ... -
好吧,所以在找到任何地方并找到其他人没有真正答案的类似帖子后,我终于明白,只要页面被刷新,如何使操作栏菜单无效。 你想在你的activity的onCreate方法中的onPageChangeListener中做到这一点,如下所示: yourViewPager.setOnPageChangeListener(new ViewPager.SimpleOnPageChangeListener() { @Override public void onPageSelected(int positio ...
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您从FragmentTransaction添加到后退状态,并使用FragmentManager pop方法从backstack中删除: FragmentManager manager = getActivity().getSupportFragmentManager(); FragmentTransaction trans = manager.beginTransaction(); trans.remove(myFrag); trans.commit(); manager.popBackStack(); ... -
如果我确实理解你,你唯一的问题是现在选项菜单没有显示,可能你可以这样做 pager.addOnPageChangeListener(new ViewPager.SimpleOnPageChangeListener(){ @Override public void onPageSelected(int position) { supportInvalidateOptionsMenu(); } }); 每次在fragment选择一个页面时,这将 ...
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通过将菜单代码更改为以下解决了问题:
Android:onCreateOptionsMenu - 删除默认菜单项(Android: onCreateOptionsMenu - Remove Default Menu Item)[2022-02-10]
正如你所看到的,我没有自己添加它 是的,你有。 它来自: getMenuInflater().inflate(R.menu.activity_name, menu); 我如何摆脱它? 删除前面提到的行。 或者,将基于Java的Menu操作移至res/menu/activity_name.xml并从该文件中删除“设置”。 As you can see, I have not added it myself Yes, you have. It is coming from: getMenuInflater() ...如何从Android中的嵌套片段中删除延迟菜单项?(How to remove lingering menu items from nested fragments in Android?)[2021-12-17]
我能在这里找到答案: https : //stackoverflow.com/a/24017261/4762063 只有Fragment可见时,解决方法是有条件地膨胀Fragment的菜单。 I was able to find an answer here: https://stackoverflow.com/a/24017261/4762063 The work around is to conditionally inflate the Fragment's menu, only if the Fra ...菜单项未显示标签(Menu items not displaying with tabs)[2022-08-17]
那么你试图在main.xml中的item标签中嵌套一个菜单 试试这个:要强制进入溢出菜单,请执行以下操作: @Override public boolean onCreateOptionsMenu(Menu menu) { menu.add(0, 2, 0, "Item 1").setShowAsAction(MenuItem.SHOW_AS_ACTION_COLLAPSE_ACTION_VIEW); return true; } SHOW_AS_ACTION_COLLAPSE_ACTION_VIEW将强制该项目进入: Android 3.0 +:Action ...相关文章
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