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哨兵在保护模式下运行(How to configure Redis 3.4 and above in master/slave config to resolve error Sentinel running on protected mode?)
哨兵在保护模式下运行(How to configure Redis 3.4 and above in master/slave config to resolve error Sentinel running on protected mode?)
我正在使用redis 3.2并在连接到来自不同机器的标记时出现以下错误：
Trying 10.5.205.105... Connected to 10.5.205.105. Escape character is '^]'. -DENIED Redis is running in protected mode because protected mode is enabled, no bind address was specified, no authentication password is requested to clients. In this mode connections are only accepted from the loopback interface. If you want to connect from external computers to Redis you may adopt one of the following solutions: 1) Just disable protected mode sending the command 'CONFIG SET protected-mode no' from the loopback interface by connecting to Redis from the same host the server is running, however MAKE SURE Redis is not publicly accessible from internet if you do so. Use CONFIG REWRITE to make this change permanent. 2) Alternatively you can just disable the protected mode by editing the Redis configuration file, and setting the protected mode option to 'no', and then restarting the server. 3) If you started the server manually just for testing, restart it with the '--protected-mode no' option. 4) Setup a bind address or an authentication password. NOTE: You only need to do one of the above things in order for the server to start accepting connections from the outside. Connection closed by foreign host.有人能帮我解决这个问题吗？
I am working with Redis 3.2 and while connecting to the sentinel from a differnt machine I get the following error:
Trying X.X.X.X... Connected to X.X.X.X. Escape character is '^]'. -DENIED Redis is running in protected mode because protected mode is enabled, no bind address was specified, no authentication password is requested to clients. In this mode connections are only accepted from the loopback interface. If you want to connect from external computers to Redis you may adopt one of the following solutions: 1) Just disable protected mode sending the command 'CONFIG SET protected-mode no' from the loopback interface by connecting to Redis from the same host the server is running, however MAKE SURE Redis is not publicly accessible from internet if you do so. Use CONFIG REWRITE to make this change permanent. 2) Alternatively you can just disable the protected mode by editing the Redis configuration file, and setting the protected mode option to 'no', and then restarting the server. 3) If you started the server manually just for testing, restart it with the '--protected-mode no' option. 4) Setup a bind address or an authentication password. NOTE: You only need to do one of the above things in order for the server to start accepting connections from the outside. Connection closed by foreign host.Can somene help me resolve this?
原文：https://stackoverflow.com/questions/41223618
更新时间：2023-05-08 22:05
最满意答案
这里发生的事情就是所谓的currying - 转换一个函数，该函数需要n个多重参数，这样才能称为函数链
让我们考虑一个函数f，它带有2个参数，即f（x，y）。 存在使得f（x，y）= g（x）（y）=（g（x））（y）的一元函数g。 函数g被称为f的curried版本。
g是期望一个参数的函数，（x），g（x）的值也是一个参数y的函数。
让我们考虑一个curried-add函数：
(define curried-add (lambda (x) (lambda (y) (+ x y)))) ((curried-add 1) 5)对（curried-add 1）的调用将返回一个函数，该函数接受一个参数，在我们的例子5中，并将其添加到1，给出和输出6。
我们可以将这些咖喱酱添加到一起以获得：
((curried-add ((curried-add 1) 2)) 3)会产生6的输出。这是因为（curried-add 1）会返回一个期望一个参数的函数，在这种情况下是2.因此，1被添加到2并产生一个函数，期望一个参数可以被添加到3我们刚刚制造。
在这种情况下，你的真实和错误的功能。
True是：
(define t (lambda (x) (lambda (y) x)))False是:(
(define f (lambda (x) (lambda (y) y)))true函数接受两个参数并返回第一个参数，false函数返回两个参数中的第二个参数。
What is happening here is something known as currying - transforming a function which takes n multiple arguments in such a way that it can be called as a chain of functions
Let us consider a function f which takes 2 arguments, i.e. f(x,y). There exists a unary function g such that f(x,y) = g(x)(y) =(g(x))(y). The function g is known as the curried version of f.
g is a function which expects one argument, (x) and the value of g(x) is also a function of one argument, y.
Let us consider a curried-add function:
(define curried-add (lambda (x) (lambda (y) (+ x y)))) ((curried-add 1) 5)The call to (curried-add 1) would return a function which takes one argument, in our case 5 and adds it to 1, giving and output of 6.
We can chain these curried-adds together to get:
((curried-add ((curried-add 1) 2)) 3)Would produce an output of 6. This is because (curried-add 1) would return a function expecting one argument, in this case 2. Therefore 1 is added to 2 and produces a function which is expecting one argument which can be added to the 3 we've just made.
In this case of your true and false functions.
True is :
(define t (lambda (x) (lambda (y) x)))False is:
(define f (lambda (x) (lambda (y) y)))The true function takes two arguments and returns the first one, the false function returns the second of the two arguments.
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