Python中单词列表中的同现矩阵(Co-occurrence Matrix from list of words in Python)

 我有一个名称列表，如： 
 
names = ['A', 'B', 'C', 'D']
 
 和一份文件清单，在每份文件中都提到了其中一些名称。 
 
document =[['A', 'B'], ['C', 'B', 'K'],['A', 'B', 'C', 'D', 'Z']]
 
 我想获得一个输出作为共现的矩阵，如： 
 
  A  B  C  D
A 0  2  1  1
B 2  0  2  1
C 1  2  0  1
D 1  1  1  0
 
 在R中有一个针对这个问题的解决方案（ 创建共现矩阵 ），但是我不能用Python来完成。 我正在考虑在熊猫中这样做，但还没有进展！ 

I have a list of names like:
 
names = ['A', 'B', 'C', 'D']
 
and a list of documents, that in each documents some of these names are mentioned.
 
document =[['A', 'B'], ['C', 'B', 'K'],['A', 'B', 'C', 'D', 'Z']]
 
I would like to get an output as a matrix of co-occurrences like:
 
  A  B  C  D
A 0  2  1  1
B 2  0  2  1
C 1  2  0  1
D 1  1  1  0
 
There is a solution (Creating co-occurrence matrix) for this problem in R, but I couldn't do it in Python. I am thinking of doing it in Pandas, but yet no progress!

原文：https://stackoverflow.com/questions/42814452