首页 \ 问答 \ Pandas选择不连续的数据帧日期切片?(Pandas select discontinuous dataframe date slices?)

Pandas选择不连续的数据帧日期切片?(Pandas select discontinuous dataframe date slices?)

我有一个带有日期时间索引的pandas DF:这个选择正常

threeyrs=actdf['01/01/2010':'12/31/2012']

但我想得到这样的东西(排除2010年):

threeyrs=actdf['01/01/2009':'12/01/2009','01/01/2011':'12/01/2012']

这给了我“不可用的类型”,这给了我一个字符串

threeyrs=actdf['01/01/2009':'12/31/2009'],actdf['01/01/2011':'12/31/2012']

有方便的方法吗? dataFrame看起来像

            Units
date    
2000-05-01   3041
2000-06-01   3079
2000-07-01   2455
2000-08-01   2671
2000-09-01   2220

I have a pandas DF with datetime index: this select works fine

threeyrs=actdf['01/01/2010':'12/31/2012']

but I'd like to get something like this (to exclude 2010):

threeyrs=actdf['01/01/2009':'12/01/2009','01/01/2011':'12/01/2012']

which gives me "unhashable type" and this gives me a string

threeyrs=actdf['01/01/2009':'12/31/2009'],actdf['01/01/2011':'12/31/2012']

Is there a convenient way? dataFrame looks like

            Units
date    
2000-05-01   3041
2000-06-01   3079
2000-07-01   2455
2000-08-01   2671
2000-09-01   2220

原文:https://stackoverflow.com/questions/20502822
更新时间:2024-01-21 14:01

最满意答案

试着看看这是否有所不同:

$user = (clone) $this->getServiceLocator()->get('User');

如果您明确告知,服务管理器每次只会为您提供一个新实例

http://framework.zend.com/manual/2.0/en/modules/zend.service-manager.quick-start.html

请注意有关共享服务的部分。 这将告诉服务管理器您每次都想要一个新的User对象,那么您将不需要像上面那样克隆该对象

'shared' => array(
        // Usually, you'll only indicate services that should _NOT_ be
        // shared -- i.e., ones where you want a different instance
        // every time.
        'User' => false,
    ),

Try to see if this makes a difference:

$user = (clone) $this->getServiceLocator()->get('User');

The service manager will only provide you with a new instance each time if you specifically tell it to

http://framework.zend.com/manual/2.0/en/modules/zend.service-manager.quick-start.html

Note the part about shared services. This would tell the service manager you want a new User object every time, then you will not need to clone the object as above

'shared' => array(
        // Usually, you'll only indicate services that should _NOT_ be
        // shared -- i.e., ones where you want a different instance
        // every time.
        'User' => false,
    ),

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