用numpy制作一个范围列表(Make a list of ranges in numpy)

 编辑： 
 
 否则，如果你从给定的字符串开始，那么你应该像这样简单地切片： 
 
a = a[1::2]
 
 
 
 第一个元素1表示您想要从第二个元素开始切片元素。 
 
 
 最后一个元素2是间隔（每两个元素） 
 
 
 空的中间元素实际上是指数上限（独占）。 如果你不放任何东西意味着你想要所有物品。 
 
 
 原版的： 
 
 请参考您之前的问题： 
 
 如何使列表元素成为字符串？ 
 
 从有a = [10, 20, 30] ， 
 
 为了从每个列表项目的第二个元素开始为给定的整数列表a获取连接字符串，可以使用[1::]从第二个元素开始将列表中的每个项目向前切片（索引1表示从第二个元素）是这样的： 
 
a = [10, 20, 30]
a = [''.join(str(x)[1::] for x in a)]

print(a)
 
 结果： 
 
['000']

Edit:
 
Else, if you start from the given string, then you should simply slice it like this:
 
a = a[1::2]
 
 
 
First element 1 means you want to slice the element starting from its second element.
 
 
The last element 2 is the interval (every two element)
 
 
The empty middle element is actually the upper index limit (exclusive). If you don't put anything means you want all items.
 
 
Original:
 
Refering from your previous question here:
 
How to make list elements into string?
 
Started from having a = [10, 20, 30],
 
In order to get the joined string for the given integer list a from the second element per list item onwards, you could slice each item of the list to from the second element onwards by using [1::] (index 1 means starting from the second element) like this:
 
a = [10, 20, 30]
a = [''.join(str(x)[1::] for x in a)]

print(a)
 
Result:
 
['000']