首页 \ 问答 \ 从控制台编辑Firebase文件元数据(Edit Firebase Files Metadata From The Console)

从控制台编辑Firebase文件元数据(Edit Firebase Files Metadata From The Console)

我知道可以编程方式编辑Firebase元数据,如下所述: https ://firebase.google.com/docs/storage/android/file-metadata

但对我来说,直接从Firebase控制台添加一些值要容易得多,但我似乎无法找到任何方法。


I know that Firebase metadata can be eddited programatically, as described here: https://firebase.google.com/docs/storage/android/file-metadata

But for me it would be a lot easier to add some values directly from the Firebase console, but I can't seem to find any way to do that.


原文:https://stackoverflow.com/questions/38306571
更新时间:2021-12-20 15:12

最满意答案

我宁愿按照以下方式简化它

(from at in address_types
join a in address 
on at.addresstype  equals a.addresstype  into tt
from ar in tt.DefaultIfEmpty()
where (ar != null && ar.addressid == 24)
select new 
 {
    at.Description,
    ar.Address1, 
    ar.Address2, 
    ar.City 
  })

我们不需要这个检查“(ja == null)”的原因是因为我们已经在这行“where(ar!= null && ar.addressid == 24)”中限制了我们的集合。

同时这个查询有效,我的POV是在SQL查询中LEFT JOIN也是多余的。 由于您的条件“a.addressid = 24”,您将不会获得NULL行,因此可以将SQL重写为INNER JOIN和LINQ查询以及

(from at in address_types
    join a in address 
    on at.addresstype  equals a.addresstype
    where at.addressid == 24
    select new 
     {
        at.Description,
        a.Address1, 
        a.Address2, 
        a.City  
      })

I would rather simplify it in following way

(from at in address_types
join a in address 
on at.addresstype  equals a.addresstype  into tt
from ar in tt.DefaultIfEmpty()
where (ar != null && ar.addressid == 24)
select new 
 {
    at.Description,
    ar.Address1, 
    ar.Address2, 
    ar.City 
  })

The reason why we don't need this check "(ja == null)" is because we already restricted our set in this line "where (ar != null && ar.addressid == 24)".

Meanwhile this query works, my POV is that LEFT JOIN is also redundant here in the SQL query. You will not get NULL rows due to your condition "a.addressid = 24" so SQL can be rewritten to INNER JOIN and LINQ query as well to

(from at in address_types
    join a in address 
    on at.addresstype  equals a.addresstype
    where at.addressid == 24
    select new 
     {
        at.Description,
        a.Address1, 
        a.Address2, 
        a.City  
      })

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