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jQuery“for”循环(jQuery “for” loop)

我想在这里写一些非常基本的jQuery代码。

我在这里做的是我希望图像在悬停时切换。 我有5个图像,当我编写5个代码时,我可以将其归档,每个图像1个。

        $('#menu > ul:first-child > li:nth-child(1)').hover(function(){
            $('li:nth-child(1) > .image-hover').toggle();
            $('li:nth-child(1) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(2)').hover(function(){
            $('li:nth-child(2) > .image-hover').toggle();
            $('li:nth-child(2) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(3)').hover(function(){
            $('li:nth-child(3) > .image-hover').toggle();
            $('li:nth-child(3) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(4)').hover(function(){
            $('li:nth-child(4) > .image-hover').toggle();
            $('li:nth-child(4) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(5)').hover(function(){
            $('li:nth-child(5) > .image-hover').toggle();
            $('li:nth-child(5) > .image').toggle();
        });

现在我想缩短代码,使用“for”循环。 我的想法是我有一个变量i,从1开始,将1加1直到5.上面的第n个孩子,而不是具体的数字,现在将成立i。 当我改变时,第n个孩子(i)将具有i的相应值。

        (function($){
            for (var i = 1; i < 6; i++) {
                $('#menu > ul:first-child > li:nth-child(i)').hover(function(){
                    $('li:nth-child(i) > .image-hover').toggle();
                    $('li:nth-child(i) > .image').toggle();
                });
            };
        })(jQuery);

尽管这个缩短的代码不起作用。

有人可以帮我弄这个吗? 非常感谢。


I am trying to write some very basic jQuery code here.

What I am doing here is I want the image to toggle when hover. I have 5 images, and I was able to archive that when I wrote 5 codes, 1 for each image.

        $('#menu > ul:first-child > li:nth-child(1)').hover(function(){
            $('li:nth-child(1) > .image-hover').toggle();
            $('li:nth-child(1) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(2)').hover(function(){
            $('li:nth-child(2) > .image-hover').toggle();
            $('li:nth-child(2) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(3)').hover(function(){
            $('li:nth-child(3) > .image-hover').toggle();
            $('li:nth-child(3) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(4)').hover(function(){
            $('li:nth-child(4) > .image-hover').toggle();
            $('li:nth-child(4) > .image').toggle();
        });

        $('#menu > ul:first-child > li:nth-child(5)').hover(function(){
            $('li:nth-child(5) > .image-hover').toggle();
            $('li:nth-child(5) > .image').toggle();
        });

Now I want to shorten the code, using the "for" loop. The idea is I have a variable i, starting from 1, increasing 1 by 1 up to 5. The nth-child above, instead of having a specific number, will now hold i. As i changes, nth-child(i) will have respective values of i.

        (function($){
            for (var i = 1; i < 6; i++) {
                $('#menu > ul:first-child > li:nth-child(i)').hover(function(){
                    $('li:nth-child(i) > .image-hover').toggle();
                    $('li:nth-child(i) > .image').toggle();
                });
            };
        })(jQuery);

This shorten code doesn't work though.

Can someone help me with this? Thanks a lot.


原文:https://stackoverflow.com/questions/23902052
更新时间:2023-06-03 17:06

最满意答案

上次我检查它是Flash。 它使用ActionScripts FileReference类。 如果要将此类功能添加到您自己的应用程序中,请查看http://swfupload.org/

一开始最令我惊讶的是,你可以拥有这种功能,没有任何消息要求用户许可。 我已经习惯了这种功能的java applet,并且要访问需要签名的文件系统,并在执行前请求用户权限。 Flash的诀窍是你只需:

  • 打开FileDialog以选择文件
  • 您可以对所选文件执行的唯一操作是上传

因此,用户没有安全风险,因为程序员永远无法访问文件系统。


Last time I checked it was Flash. It uses ActionScripts FileReference class. Check out http://swfupload.org/ if you want to add this kind of functionality to your own application.

What surprised me the most in the beginning was that you could have this kind of functionality with no message asking for user permission whatsoever. I was used to java applets for this kind of feature, and to access the file system they need to be signed, and ask for user permission before execution. The trick with Flash is that you just :

  • open a FileDialog to select files
  • the only thing you can do with the selected files is uploading

So there is no security risk for the user, as the programmer never gets access to the file system.

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