案例陈述执行步骤(Case statement execution steps)

 我有以下案例陈述： 
 
A = 1

case A is                      
    when 1          => A = 2;
                    => Run;      
    when 3 .. 15    => null;   
    when 16 | 17    => Jump;    
    when 2 | 18..35 => Swing;     
    when others     => Nothing; 
end case;
 
 所以case语句将转到1，因为A初始化为1.然后A将等于2，然后代码将执行Run。 此时代码是否退出case语句，还是会执行Swing，因为A被更改为2的值？ 

I have the following case statement:
 
A = 1

case A is                      
    when 1          => A = 2;
                    => Run;      
    when 3 .. 15    => null;   
    when 16 | 17    => Jump;    
    when 2 | 18..35 => Swing;     
    when others     => Nothing; 
end case;
 
So the case statement will go to 1 since A is initialized to 1. A will then be equal to 2, and then the code will execute Run. Does the code exit out of the case statement at this point, or will Swing be executed because A was changed to a value of 2?

原文：https://stackoverflow.com/questions/29957285