正则表达式字符串捕获JavaScript(regex string capturing javascript)

 我是javascript的正则表达式的新手。 我有一个类似下面的字符串： 
 
 
 
 “ 和这里的东西（这里的东西和 （这里的东西，这里有什么东西）别的东西或其他东西）asdf（ 或 asdfas） 和这里的东西或其他什么东西（这里还有别的东西或别的东西）” 
 
 
 从上面的字符串，我试图根据以下规则捕获文本组： 
 
 
 
 捕获以"and"或"or"开头并以"or"或"and"结尾的行 
 
 
 捕获的行可以有许多括号。 
 
 
 如果运算符"or"或"and"在括号中，则忽略它们 
 
 
 从上面的字符串，我期待如下所示的结果组 
 
 
 
 
  
 和这里的东西（这里的东西和 （这里的东西和这里的东西）别的东西或其他东西）asdf（ 或 asdfas） 
 
  
 还有什么在这里 
 
  
 或者这里的东西（这里的其他东西和其他东西或其他东西） 
 
 
 
 
 我尝试了许多正则表达式，并且接近我想要的正则表达式是： 
 
(and|or)\s.((?!(and|or)).)*
 
 我也可以使用非正则表达式解决方案。 

I am new to regex in javascript. I have a string something like below:
 
 
 
"and something here ( something else here and (something here and something here) something else or something else) asdf (or asdfas) and something here or something here ( something else here and something else or something else)"
 
 
From the above string, I am trying to capture group of text based on the following rules:
 
 
 
Capture a line which starts with "and" or "or" and ends with "or" or "and"
 
 
A captured line can have many parenthesis.
 
 
If the operators "or" or "and" are in parenthesis, then ignore them
 
 
From the above string, I am expecting group of result as shown below
 
 
 
 
  
and something here ( something else here and (something here and something here) something else or something else) asdf (or asdfas)
 
  
and something here
 
  
or something here ( something else here and something else or something else)
 
 
 
 
I have tried many regexes and the one which is close to what I want is:
 
(and|or)\s.((?!(and|or)).)*
 
I am ok with a non-regex solution too.

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