正则表达式用于读取由分号分隔的字符串并捕获特殊字符。(Regex for reading strings separated by semi-colon and capturing special characters. Python)

 我有一个字符串如下： 
 
mod_str ="10Deamidated; 12Gln->pyro-Glu"
 
 我想将字符串的两个部分分成列表的元素，其中包含整数和字符串的元组，如下所示： 
 
[('10', 'Deamidated'), ('12', 'Gln->pyro-Glu')]
 
 我使用以下代码来捕获字符串，但我不知道如何包含特殊字符。 
 
match_pattern = re.compile(r'(\d+)(\w+)')
items = match_pattern.findall(mod_str)
 
 到目前为止，输出看起来像这样： 
 
[('10', 'Deamidated'), ('12', 'Gln')]
 
 对于如何解决这个问题，有任何的建议吗？ 

I have a string as follows:
 
mod_str ="10Deamidated; 12Gln->pyro-Glu"
 
I want to separate the two parts of the string into elements of a list with tuples containing integer and string as follows:
 
[('10', 'Deamidated'), ('12', 'Gln->pyro-Glu')]
 
I am using the following code to capture the string but I am not sure how to include the special characters. 
 
match_pattern = re.compile(r'(\d+)(\w+)')
items = match_pattern.findall(mod_str)
 
So far the output looks like this:
 
[('10', 'Deamidated'), ('12', 'Gln')]
 
Any suggestions on how to fix this?

原文：https://stackoverflow.com/questions/23093622