用本地指针分段错误？(Segmentation fault with local pointer?)

 这是一个函数调用（因此它只是整个程序的一部分）。 它会产生分段错误。 我猜这是由“指针是一个局部变量”引起的？ 
 
int fileExists(const char *fname){
    int i = 0;
    fseek(fs, sizeof(NODE)*i, SEEK_SET);
    NODE* pointer;
    fread(pointer, sizeof(NODE), 1, fs);
    return 1;
}
 
 更新： 
 
typedef struct node {
    char fname[MAX_NAME];
    short fstart;
} NODE;

int findStart (const char *fname){
    fs = fopen("Directory", "w+");
    NODE* pointer = malloc(sizeof(NODE));
    int i;
    for(i=0;i<numberNodes;i++){
        fseek(fs, sizeof(NODE)*i, SEEK_SET);
        fread(pointer, sizeof(NODE), 1, fs);
        if(strcmp(pointer->fname, fname)==0)
            return pointer->fstart;
    }
    return 0;
}
 
 因此，如果我想运行目录文件中的节点并找到正确节点的“fstart”，我是否可以实现这一点而无需释放分配给“指针”的内存？ 

This is a function call (so it is just a part of the whole program). It will generate a segmentation fault. I guess it is caused by "pointer being a local variable"?
 
int fileExists(const char *fname){
    int i = 0;
    fseek(fs, sizeof(NODE)*i, SEEK_SET);
    NODE* pointer;
    fread(pointer, sizeof(NODE), 1, fs);
    return 1;
}
 
Updated:
 
typedef struct node {
    char fname[MAX_NAME];
    short fstart;
} NODE;

int findStart (const char *fname){
    fs = fopen("Directory", "w+");
    NODE* pointer = malloc(sizeof(NODE));
    int i;
    for(i=0;i<numberNodes;i++){
        fseek(fs, sizeof(NODE)*i, SEEK_SET);
        fread(pointer, sizeof(NODE), 1, fs);
        if(strcmp(pointer->fname, fname)==0)
            return pointer->fstart;
    }
    return 0;
}
 
So if I want to run through the nodes in the directory file and find the "fstart" of the right node, can I achieve that without the need of free-ing the memory allocated to "pointer"?

原文：https://stackoverflow.com/questions/8147619