指数泰勒级数(Exponential Taylor Series)

 这是我到目前为止的代码，因为我仍在试图弄清楚如何设置它，所以有点乱，但我无法弄清楚如何获得输出。 该代码应该采用指数的泰勒级数多项式，并检查获得近似值所需的迭代次数。 
 
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
/*Prototype for functions used*/
double factorial (int);

int main()
{
   double input = 0;
   double exp_val;
   double delta = 1;
   int f =0;
   int n = 0;
   double taylor;
   int total;
   printf("Plese enter the exponent to check for convergence:\n");
   scanf("%lf", &input);
   exp_val = exp(input);
   printf("  #     Iter      e^X      Sum     Diff\n");
   printf("----   ------   -------   -----  --------");

   while(delta > 0.00001)
   {
      f = factorial(n);
      taylor = ((pow(input,n))/ f);
      delta = (exp_val - taylor);
      printf("%d %f %f %f/n", (n+1), exp_val, taylor, delta);
      n++;
   }
   system("pause");


}

double factorial (int n)
{
  int r = 0;
  int sum = 1;
  int total = 0;
  if (n == 0)
    return total =1;
  else
  {
     for(r; r<n; r++)
     {
        sum = sum * r;
        total = sum + 1;

     }

     return total;
  }

}

This is the code I have so far, which is a little messy since I am still trying to figure out how to set it up, but I cannot figure out how to get the output. This code is supposed to take a Taylor Series polynomial of an exponential, and check the amount of iterations it takes to get the approximation. 
 
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
/*Prototype for functions used*/
double factorial (int);

int main()
{
   double input = 0;
   double exp_val;
   double delta = 1;
   int f =0;
   int n = 0;
   double taylor;
   int total;
   printf("Plese enter the exponent to check for convergence:\n");
   scanf("%lf", &input);
   exp_val = exp(input);
   printf("  #     Iter      e^X      Sum     Diff\n");
   printf("----   ------   -------   -----  --------");

   while(delta > 0.00001)
   {
      f = factorial(n);
      taylor = ((pow(input,n))/ f);
      delta = (exp_val - taylor);
      printf("%d %f %f %f/n", (n+1), exp_val, taylor, delta);
      n++;
   }
   system("pause");


}

double factorial (int n)
{
  int r = 0;
  int sum = 1;
  int total = 0;
  if (n == 0)
    return total =1;
  else
  {
     for(r; r<n; r++)
     {
        sum = sum * r;
        total = sum + 1;

     }

     return total;
  }

}

原文：https://stackoverflow.com/questions/22122846