首页 \ 问答 \ 正则表达式的x位数和只有一个连字符?(Regular expression for x number of digits and only one hyphen?)

正则表达式的x位数和只有一个连字符?(Regular expression for x number of digits and only one hyphen?)

我做了以下正则表达式:

(\d{5}|\d-\d{4}|\d{2}-\d{3}|\d{3}-\d{2}|\d{4}-\d)

它似乎工作。 也就是说,它会匹配一个5位数字或一个5位数字,只有1个连字符,但连字符不能是前导或末尾。

我想要一个类似的正则表达式,但是对于一个25位数的数字。 如果我使用与上面相同的策略,那么正则表达式将会很长。

任何人都可以建议一个更简单的正则表达式?

附加说明:我将这个正则表达式放入一个将由ASP.NET应用程序使用的XML文件中。 我无法访问.net后端代码。 但我怀疑他们会这样做:

Match match = Regex.Match("Something goes here", "my regex", RegexOptions.None);

I made the following regex:

(\d{5}|\d-\d{4}|\d{2}-\d{3}|\d{3}-\d{2}|\d{4}-\d)

And it seems to work. That is, it will match a 5 digit number or a 5 digit number with only 1 hyphen in it, but the hyphen can not be the lead or the end.

I would like a similar regex, but for a 25 digit number. If I use the same tactic as above, the regex will be very long.

Can anyone suggest a simpler regex?

Additional Notes: I'm putting this regex into an XML file which is to be consumed by an ASP.NET application. I don't have access to the .net backend code. But I suspect they would do something liek this:

Match match = Regex.Match("Something goes here", "my regex", RegexOptions.None);

原文:https://stackoverflow.com/questions/18389043
更新时间:2023-09-17 19:09

最满意答案

https://jsfiddle.net/9Luvrvc1/1/

您可以使用相同的代码,在计数器功能处使用减号:

$(document).ready(function() {
    var count;
    var interval;

    $(".ca-top").on('mouseover', function() {
        var div = $('.navbar-nav.categories');

        intervalDown = setInterval(function(){
            count = count || 1;
            var pos = div.scrollTop();
            div.scrollTop(pos + count);
        }, 10);
    }).click(function() {
        if (count < 6) {
             count = count+1;
        }
    }).on('mouseout', function() {
        // Uncomment this line if you want to reset the speed on out
        count = 0;
        clearInterval(intervalDown);
    });

    $(".ca-bottom").on('mouseover', function() {
        var div = $('.navbar-nav.categories');

        intervalUp = setInterval(function(){
            count = count || 1;
            var pos = div.scrollTop();
            div.scrollTop(pos - count);
        }, 10);
    }).click(function() {
        if (count > 6) {
             count = count-1;
        }
    }).on('mouseout', function() {
        // Uncomment this line if you want to reset the speed on out
        count = 0;
        clearInterval(intervalUp);
    });    

});

但是,您可以尝试创建类似滚动(方向)的功能 - 这将使您的代码更短,更好阅读。


https://jsfiddle.net/9Luvrvc1/1/

You can just use the same code, with a minus at the counter function:

$(document).ready(function() {
    var count;
    var interval;

    $(".ca-top").on('mouseover', function() {
        var div = $('.navbar-nav.categories');

        intervalDown = setInterval(function(){
            count = count || 1;
            var pos = div.scrollTop();
            div.scrollTop(pos + count);
        }, 10);
    }).click(function() {
        if (count < 6) {
             count = count+1;
        }
    }).on('mouseout', function() {
        // Uncomment this line if you want to reset the speed on out
        count = 0;
        clearInterval(intervalDown);
    });

    $(".ca-bottom").on('mouseover', function() {
        var div = $('.navbar-nav.categories');

        intervalUp = setInterval(function(){
            count = count || 1;
            var pos = div.scrollTop();
            div.scrollTop(pos - count);
        }, 10);
    }).click(function() {
        if (count > 6) {
             count = count-1;
        }
    }).on('mouseout', function() {
        // Uncomment this line if you want to reset the speed on out
        count = 0;
        clearInterval(intervalUp);
    });    

});

However you can try to make a function like scroll(direction) - which will make your code shorter and better to read.

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