是否可以使用JAXB基于某些属性值获取XML元素？(Is it possible to get XML elements based on some attribute value/s using JAXB?)

 我使用名为Height.xml JAXB创建了一个XML文件。 结构如下所示。 
 
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<heightList>
    <measurement id="5">
        <height>4'4"</height>
    </measurement>
    <measurement id="4">
        <height>4'3"</height>
    </measurement>
    <measurement id="3">
        <height>4'2"</height>
    </measurement>
    <measurement id="2">
        <height>4'1"</height>
    </measurement>
    <measurement id="1">
        <height>4'0"</height>
    </measurement>
</heightList>
 
 可以将此XML文件解组为List<Height> ，如下所示。 
 
JAXBContext jaxb=JAXBContext.newInstance(HeightList.class);
File file=new File("Height.xml");
List<Height> heightList = ((HeightList) jaxb.createUnmarshaller().unmarshal(file)).getList();
 
 是否可以根据其属性id获取XML元素，以便取代List<Height> ，只获取一个Height类型的对象？ id属性是唯一的。 
 
 
 相关课程： 
 
 高度： 
 
public final class Height implements Serializable
{
    private Integer id;
    private String height;
    private static final long serialVersionUID = 1L;

    public Height() {}

    @XmlAttribute(name = "id")
    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getHeight() {
        return height;
    }

    public void setHeight(String height) {
        this.height = height;
    }
}
 
 HeightList： 
 
@XmlRootElement(name = "heightList")
@XmlAccessorType(XmlAccessType.PROPERTY)
public final class HeightList implements Serializable
{
    @XmlElement(name="measurement")
    private List<Height>list;
    private static final long serialVersionUID = 1L;

    public HeightList() {}

    public HeightList(List<Height> list) {
        this.list = list;
    }

    public List<Height> getList() {
        return list;
    }
}

I have created an XML file using JAXB named Height.xml. The structure looks like the following.
 
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<heightList>
    <measurement id="5">
        <height>4'4"</height>
    </measurement>
    <measurement id="4">
        <height>4'3"</height>
    </measurement>
    <measurement id="3">
        <height>4'2"</height>
    </measurement>
    <measurement id="2">
        <height>4'1"</height>
    </measurement>
    <measurement id="1">
        <height>4'0"</height>
    </measurement>
</heightList>
 
This XML file can be unmarshalled to a List<Height> as follows.
 
JAXBContext jaxb=JAXBContext.newInstance(HeightList.class);
File file=new File("Height.xml");
List<Height> heightList = ((HeightList) jaxb.createUnmarshaller().unmarshal(file)).getList();
 
Is it possible to get an XML element based on its attribute id so that instead of List<Height>, only one object of type Height is fetched? The id attribute is unique.
 
 
The associated classes:
 
Height:
 
public final class Height implements Serializable
{
    private Integer id;
    private String height;
    private static final long serialVersionUID = 1L;

    public Height() {}

    @XmlAttribute(name = "id")
    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getHeight() {
        return height;
    }

    public void setHeight(String height) {
        this.height = height;
    }
}
 
HeightList:
 
@XmlRootElement(name = "heightList")
@XmlAccessorType(XmlAccessType.PROPERTY)
public final class HeightList implements Serializable
{
    @XmlElement(name="measurement")
    private List<Height>list;
    private static final long serialVersionUID = 1L;

    public HeightList() {}

    public HeightList(List<Height> list) {
        this.list = list;
    }

    public List<Height> getList() {
        return list;
    }
}

原文：