有没有更好的方法来使用Ext.apply将子/子对象组合到另一个对象中？(Is there a better way to use Ext.apply to combine child/subobjects into another object?)

 我试图将对象属性从objA应用到objB，但是我意识到Ext.apply有缺陷（或祝福？），它只以一种方式应用第一级对象。 
 
 例： 
 
var objA = {
    name: 'objA',
    baseParams: {
        cols: [1,2,3,4,5]
    }
};

//used in subclass
var objB = {
    name: 'objB',
    baseParams: {
        limit: 50,
        sort: 'name'
    }
};

//used in baseclass
var objC = {
    name: 'objC',
    baseParams: {
        as_hash: true,
        limit: 20
    }
};

Ext.apply(objB,objA); //used in subclass
Ext.apply(objC,objB); //used in baseclass
 
 示例将输出： 
 
obj = {
    name: 'objA',
    baseParams: {
        cols: [1,2,3,4,5]
    }
};
 
 我想这个输出，而不是（预期输出）： 
 
obj = {
    name: 'objA',
    baseParams: {
        cols: [1,2,3,4,5],
        as_hash: true,
        limit: 50,
        sort: 'name'
    }
};
 
 没有这样做我怎么能做到这一点？ 
 
// subclass:
var bpTemp = {};
bpTemp.baseParams = Ext.apply(objB.baseParams, objA.baseParams);
Ext.apply(objB,objA); 
Ext.apply(objB,bpTemp); 

// base class: 
var bpTemp = {};
bpTemp.baseParams = Ext.apply(objC.baseParams, objB.baseParams);
Ext.apply(objC,objB); 
Ext.apply(objC,bpTemp); 

I'm trying to apply the object properties from objA to objB but I realised Ext.apply is flawed (or blessing?) in a way where it only applies first level objects together. 
 
Example: 
 
var objA = {
    name: 'objA',
    baseParams: {
        cols: [1,2,3,4,5]
    }
};

//used in subclass
var objB = {
    name: 'objB',
    baseParams: {
        limit: 50,
        sort: 'name'
    }
};

//used in baseclass
var objC = {
    name: 'objC',
    baseParams: {
        as_hash: true,
        limit: 20
    }
};

Ext.apply(objB,objA); //used in subclass
Ext.apply(objC,objB); //used in baseclass
 
Example will output:
 
obj = {
    name: 'objA',
    baseParams: {
        cols: [1,2,3,4,5]
    }
};
 
I'd like this output instead (expected output): 
 
obj = {
    name: 'objA',
    baseParams: {
        cols: [1,2,3,4,5],
        as_hash: true,
        limit: 50,
        sort: 'name'
    }
};
 
How can I achieve this without doing this?
 
// subclass:
var bpTemp = {};
bpTemp.baseParams = Ext.apply(objB.baseParams, objA.baseParams);
Ext.apply(objB,objA); 
Ext.apply(objB,bpTemp); 

// base class: 
var bpTemp = {};
bpTemp.baseParams = Ext.apply(objC.baseParams, objB.baseParams);
Ext.apply(objC,objB); 
Ext.apply(objC,bpTemp); 

原文：https://stackoverflow.com/questions/5216565