Yii2禁用供应商模块的资产(Yii2 disable asset of a vendor module)

 我不认为有任何需要使用csape ，你可以只使用spline 。 从spline的文档： 
 
 
 
 如果Y是包含两个值而不是x具有条目的向量，则Y中的第一个和最后一个值将用作三次样条曲线的endlopes。 
 
 
 此外，样条线允许您直接获取插值的yy值，因此： 
 
x = [3 4 7 9];
y = [2 1 2 0.5];
xx = 0:0.1:10;
yy = spline(x,[0 y 0], xx);
plot(xx,yy)
 
 这给了我下面的情节。 
 
  
 
 看看这个，边界处的斜率为零（x = 3和x = 9），这就是我们所要求的“边界处零梯度”的“夹紧”样条。 如果您希望超出边界的零梯度，我建议您执行以下操作： 
 
yy(xx<x(1)) = y(1);
yy(xx>x(length(x))) = y(length(y));
 
 赠送： 
 
  
 
 编辑 
 
 这在末端结处给出了连续的y函数，但是y'在末端结处不平滑。 如果您希望y '平滑，可以填充输入数组并将其用作spline函数的输入。 这会给你一些振荡，如下所示，这可能是也可能不是你想要的。 
 
% Spline on padded input arrays
x = [0 1 2 3 4 7 9 10 11 12];
y = [2 2 2 2 1 2 0.5 0.5 0.5 0.5];
yy = spline(x,y, xx);
 
  

I don't think there's any need to use csape, you can just use spline. From the documentation for spline:
 
 
 
If Y is a vector that contains two more values than x has entries, the first and last value in Y are used as the endslopes for the cubic spline.
 
 
Also, spline allows you to obtain the interpolated yy values directly, so:
 
x = [3 4 7 9];
y = [2 1 2 0.5];
xx = 0:0.1:10;
yy = spline(x,[0 y 0], xx);
plot(xx,yy)
 
This gives me the plot below.
 
 
Looking at this, the slope is zero at the boundaries (x=3 and x=9), which is what we are asking of a 'clamped' spline with zero gradient at the boundaries. If you wish to have zero gradient beyond the boundaries, I would recommend just doing the following:
 
yy(xx<x(1)) = y(1);
yy(xx>x(length(x))) = y(length(y));
 
Giving:
 
 
Edit
 
This gives a continuous y function at the end-knots, but y' is not smooth at the end-knots. If you would like y' to be smooth you could pad your input arrays and use this as the input to your spline function. This would give you some oscillations as shown below, though, which may or may not be what you want.
 
% Spline on padded input arrays
x = [0 1 2 3 4 7 9 10 11 12];
y = [2 2 2 2 1 2 0.5 0.5 0.5 0.5];
yy = spline(x,y, xx);