如何使选项接受任意数量的参数(How do I make an option accept an arbitrary number of arguments)

 我正在尝试编写一个shell脚本，其中包含在每次运行中使用不同数量值的选​​项，例如 
 
 运行1： 
 
./myscript --input <file1> <file2> --output <folder1>
 
 运行2： 
 
./myscript --input <file1> <file2> <file3> --output <folder1> <folder2>
 
 我尝试使用getopts如下： 
 
while getopts ":i:o:" opt; do
  case $opt in
  i)
    echo "treatment files are: $OPTARG" >&2
    infiles="${OPTARG}"
  ;;
  o)
    echo "control files are: $OPTARG" >&2
    outdir="${OPTARG}"
  ;;
  \?)
    echo "Invalid option: -$OPTARG" >&2
    exit 1
  ;;
  :)
    echo "Option -$OPTARG requires an argument." >&2
    exit 1
  ;;
  esac
done
 
 但是，我发现为“-i”选项输入可变数量值的唯一方法是引用（“file1 file2”），这阻止我/用户使用命令行的自动完成功能来帮助生成文件路径。 此选项似乎也不允许我使用“--input”语法来传递选项。 
 
 有人可以帮忙吗？ 
 
 非常感谢。 

I am trying to write a shell script with options that take different numbers of values in each run, e.g.
 
Run 1:
 
./myscript --input <file1> <file2> --output <folder1>
 
Run 2:
 
./myscript --input <file1> <file2> <file3> --output <folder1> <folder2>
 
I tried using getopts as follows:
 
while getopts ":i:o:" opt; do
  case $opt in
  i)
    echo "treatment files are: $OPTARG" >&2
    infiles="${OPTARG}"
  ;;
  o)
    echo "control files are: $OPTARG" >&2
    outdir="${OPTARG}"
  ;;
  \?)
    echo "Invalid option: -$OPTARG" >&2
    exit 1
  ;;
  :)
    echo "Option -$OPTARG requires an argument." >&2
    exit 1
  ;;
  esac
done
 
However, the only way I found to input variable amounts of values for the "-i" option is by quotation ("file1 file2"), which prevents me/the user to use the autocomplete function of the command line to help generating the file path. Also this option does not seem allow me to use "--input" syntax to pass the options.
 
Anybody can help?
 
Thanks a lot.

原文：https://stackoverflow.com/questions/50517122