首页 \ 问答 \ 将项添加到listview1中,如果该项已经在listview1中或已替换,则删除该项(Adding item into listview1 and remove if the item has already in the listview1 or replace)

将项添加到listview1中,如果该项已经在listview1中或已替换,则删除该项(Adding item into listview1 and remove if the item has already in the listview1 or replace)

我有listview1有2列。 我已经有了添加项目的代码但我的问题是当我再次添加listview1的相同项目时,它显示重复项,当我继续添加相同的项目时,listview中的项目正在增加相同的数据。

我需要的例子:

listview1已经在第1列= 1和第2列= A中的数据时,我想再次添加像第1列= 1和第2列= B这样的数据。我有2个解决方案,我尝试编码但没有运气。 我的2个解决方案是:

  1. 我只想更新第二列中的数据,从“A”到“B”但是具有相同的第一列数据,并且没有其他项目将被添加到列表视图中,就像更新/替换它一样。

要么

  1. 删除将导致重复的项目并添加相同的项目,这样就不会有重复项。

这是我添加项目的代码:

 Private Sub rbChoiceA_Checked(ByVal sender As Object, ByVal e As EventArgs)

    Dim rbA As RadioButton = TryCast(sender, RadioButton)
    Dim str As String = rbA.Parent.Name
    str = str.Remove(0, 6)
    lab1.Text = str
    Dim item As ListViewItem
    Dim row As String() = New String(2) {}
    row(0) = str
    row(1) = rbA.Text
    item = New ListViewItem(row)
    ListView1.Items.Add(item)

End Sub

我只是需要帮助来添加我的问题的代码。 非常感谢您的回答。 提前致谢!


I have listview1 with 2 columns. I already have a code for adding items but my problem is when I add again the same item in listview1, it shows duplicates and when I continue to add the same item, the items in listview are increasing with same data.

Example for what I need:

When listview1 has already a data in 1st column = 1 and in 2nd column = A, and I want to add again with a data like these 1st column = 1 and in 2nd column = B. I have 2 solutions and I try to code it but with no luck. My 2 solutions is these:

  1. I just want to update only the data in 2nd column, from "A" to "B" but with the same 1st column data and no additional item will be added into listview like nothing just update/replace it.

OR

  1. Remove the item that will cause duplication and add the same item so there will be no duplicates.

Here's my code for adding item:

 Private Sub rbChoiceA_Checked(ByVal sender As Object, ByVal e As EventArgs)

    Dim rbA As RadioButton = TryCast(sender, RadioButton)
    Dim str As String = rbA.Parent.Name
    str = str.Remove(0, 6)
    lab1.Text = str
    Dim item As ListViewItem
    Dim row As String() = New String(2) {}
    row(0) = str
    row(1) = rbA.Text
    item = New ListViewItem(row)
    ListView1.Items.Add(item)

End Sub

I just need help to add the code for my problem. Your answers is highly appreciated. Thanks in advance!


原文:https://stackoverflow.com/questions/40832127
更新时间:2022-06-02 06:06

最满意答案

尝试以下操作:

who | awk '{w[$1]++} END { for (x in w) { print x,"has "w[x]"active sessions" }}'

Try the following:

who | awk '{w[$1]++} END { for (x in w) { print x,"has "w[x]"active sessions" }}'

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