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xsd：XSLT 1.0中的boolean与XSLT 2.0(xsd:boolean in XSLT 1.0 vs XSLT 2.0)

 根据这个答案的前几行，我推断出来  
 <xsl:if test="not(@dothis) or @dothis=true()">  
 属性dothis将被视为节点集而不是布尔值。 此外，除非未定义，否则此值将始终为true。 但是，我观察到在XLST 2.0转换中（在JAVA中使用SAXON引擎），上述条件得到满足并且如下所示的节点  
 <entry node="node1" dothis="false">Dr.Manhattan in rebirth!</entry>  
 被适当跳过。  
 但是，当我使用XSLT 1.0（在Perl中使用libxslt引擎）时，我必须将条件修改为  
 <xsl:if test="not(@dothis) or (@dothis = 'true')">  
 然后才会跳过像node1这样的节点。  
 为什么Perl XSLT 1.0引擎无法正确理解true()并且需要将值显式为'true' ？ 

Based on first few lines of this answer, I infer that  
<xsl:if test="not(@dothis) or @dothis=true()"> 
attribute dothis will be treated as node-set and not boolean value. Also, this value will always be true unless its not defined. However, I have observed that in XLST 2.0 transformation (using SAXON engine in JAVA), above condition gets satisfied and nodes such as following  
<entry node="node1" dothis="false">Dr.Manhattan in rebirth!</entry> 
are skipped appropriately. 
However when I use XSLT 1.0 (using libxslt engine in Perl), I have to modify the condition as 
<xsl:if test="not(@dothis) or (@dothis = 'true')"> 
and only then does the nodes like node1 are skipped. 
Why can't the Perl XSLT 1.0 engine understands true() correctly and needs the value as 'true' explicitly?

原文：https://stackoverflow.com/questions/39017729

更新时间：2023-02-02 08:02

最满意答案

 您需要解析val，并设置ops的顺序（如果需要），例如：  
$(document).ready(function() {
  $("input").blur(
    function() {
      var sum = 0;
      $('input[name="y"]').val(function() {
        var valA = parseFloat($('input[name="a"]').val()),
            valB = parseFloat($('input[name="b"]').val()),
            valE = parseFloat($('input[name="e"]').val()),
            sum = (valA + valB) - valE;//set your order of ops here
        return sum.toFixed(2);
      });
    }
  );
});
 
 请参阅此更新 

You need to parse the vals, and set your order of ops (if need be), like: 
$(document).ready(function() {
  $("input").blur(
    function() {
      var sum = 0;
      $('input[name="y"]').val(function() {
        var valA = parseFloat($('input[name="a"]').val()),
            valB = parseFloat($('input[name="b"]').val()),
            valE = parseFloat($('input[name="e"]').val()),
            sum = (valA + valB) - valE;//set your order of ops here
        return sum.toFixed(2);
      });
    }
  );
});
 
See this update

xsd：XSLT 1.0中的boolean与XSLT 2.0(xsd:boolean in XSLT 1.0 vs XSLT 2.0)

最满意答案

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