Windows XP，Vista和7在开发方面的主要差异[关闭](Which Is The Major Differences Between Windows XP, Vista And 7 At The Development Side [closed])

 首先，它不反转位，它反转它们（只有最右边的位和最左边的位之间的位置设置为1）。 
 
 其次，它是如何工作的： 
 
int binaryReverse(int toReverse)
{
    int reversed = 0;
    while (toReverse > 0)
    {
        reversed  *= 2;             // shift the output one bit to the left
        reversed  += toReverse % 2; // set the rightmost bit in the output to the value of the rightmost bit in the input
        toReverse /= 2;             // shift the input one bit to the right
    }
    return reversed;
}
 
 第三，这是一个可能更易读的版本（虽然它必须将输入视为unsigned ）： 
 
int binaryReverse(unsigned int toReverse)
{
    int reversed = 0;
    while (toReverse > 0)
    {
        reversed  <<= 1;             // shift the output one bit to the left
        reversed   |= toReverse & 1; // set the rightmost bit in the output to the value of the rightmost bit in the input
        toReverse >>= 1;             // shift the input one bit to the right
    }
    return reversed;
}

First of all, it doesn't invert the bits, it reverses them (and only those between the rightmost bit and the leftmost bit which is set to 1).
 
Second, here is how it works:
 
int binaryReverse(int toReverse)
{
    int reversed = 0;
    while (toReverse > 0)
    {
        reversed  *= 2;             // shift the output one bit to the left
        reversed  += toReverse % 2; // set the rightmost bit in the output to the value of the rightmost bit in the input
        toReverse /= 2;             // shift the input one bit to the right
    }
    return reversed;
}
 
Third, here is a possibly more readable version (though it has to take the input as unsigned):
 
int binaryReverse(unsigned int toReverse)
{
    int reversed = 0;
    while (toReverse > 0)
    {
        reversed  <<= 1;             // shift the output one bit to the left
        reversed   |= toReverse & 1; // set the rightmost bit in the output to the value of the rightmost bit in the input
        toReverse >>= 1;             // shift the input one bit to the right
    }
    return reversed;
}