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VBA错误:操作没有足够的内存(VBA error: not enough memory for the operation)

这个脚本给我一个错误,因为它消耗了太多的资源。 我能做些什么来解决这个问题?

Dim oSht As Worksheet
Dim i As Long, j As Integer
Dim LRow As Long, LCol As Long
Dim Email1Col As Integer, Email2Col As Integer, Email3Col As Integer
Dim arr As Variant
Dim SplEmail3 As String


'Definitions
Set oSht = ActiveSheet
Email1Col = 6
Email2Col = 7
Email3Col = 8
'-----------

With oSht
'LRow = .Range("G" & .Rows.Count).End(xlUp).Row
LRow = 1048576
'LCol = .Cells(1, .Columns.Count).End(xlToLeft).Column
End With

For i = 2 To LRow
    'If oSht.Rows(i + 1).EntireRow = 0 Then GoTo Skip
    If Cells(i, Email1Col).Value <> "" Or Cells(i, Email3Col).Value <> "" Then
        If Cells(i, Email2Col) <> "" Then
            'email2 to new row + copy other data
            Rows(i + 1).EntireRow.Insert
            oSht.Rows(i + 1).EntireRow.Value = oSht.Rows(i).EntireRow.Value
            Range(Cells(i + 1, Email1Col), Cells(i + 1, Email3Col)).ClearContents
            Cells(i + 1, Email1Col) = Cells(i, Email2Col)
            'email3 to new row + copy other data
        End If
        If Cells(i, Email3Col) <> "" Then
            arr = Split(Cells(i, Email3Col), ",", , 1)
            For j = 0 To UBound(arr)
                'split into single emails
                SplEmail3 = Replace((arr(j)), " ", "", 1, , 1)
                'repeat the process for every split
                Rows(i + 2 + j).EntireRow.Insert
                oSht.Rows(i + 2 + j).EntireRow.Value = oSht.Rows(i).EntireRow.Value
                Range(Cells(i + 2 + j, Email1Col), Cells(i + 2 + j, Email3Col)).ClearContents
                Cells(i + 2 + j, Email1Col) = SplEmail3
            Next j
        End If
        Range(Cells(i, Email2Col), Cells(i, Email3Col)).ClearContents
    Else
        Rows(i).EntireRow.Delete
    End If
Skip:
Next i

样本数据:

col1, col2,..., col6, col7 ,  col8
name, bla, ...,mail1,mail2,(mail3,mail4,mail5)

需要成为这样的:

col1, col2,..., col6
name, bla, ...,mail1

This script is giving me an error because it consumes too much resources. What can I do to fix that?

Dim oSht As Worksheet
Dim i As Long, j As Integer
Dim LRow As Long, LCol As Long
Dim Email1Col As Integer, Email2Col As Integer, Email3Col As Integer
Dim arr As Variant
Dim SplEmail3 As String


'Definitions
Set oSht = ActiveSheet
Email1Col = 6
Email2Col = 7
Email3Col = 8
'-----------

With oSht
'LRow = .Range("G" & .Rows.Count).End(xlUp).Row
LRow = 1048576
'LCol = .Cells(1, .Columns.Count).End(xlToLeft).Column
End With

For i = 2 To LRow
    'If oSht.Rows(i + 1).EntireRow = 0 Then GoTo Skip
    If Cells(i, Email1Col).Value <> "" Or Cells(i, Email3Col).Value <> "" Then
        If Cells(i, Email2Col) <> "" Then
            'email2 to new row + copy other data
            Rows(i + 1).EntireRow.Insert
            oSht.Rows(i + 1).EntireRow.Value = oSht.Rows(i).EntireRow.Value
            Range(Cells(i + 1, Email1Col), Cells(i + 1, Email3Col)).ClearContents
            Cells(i + 1, Email1Col) = Cells(i, Email2Col)
            'email3 to new row + copy other data
        End If
        If Cells(i, Email3Col) <> "" Then
            arr = Split(Cells(i, Email3Col), ",", , 1)
            For j = 0 To UBound(arr)
                'split into single emails
                SplEmail3 = Replace((arr(j)), " ", "", 1, , 1)
                'repeat the process for every split
                Rows(i + 2 + j).EntireRow.Insert
                oSht.Rows(i + 2 + j).EntireRow.Value = oSht.Rows(i).EntireRow.Value
                Range(Cells(i + 2 + j, Email1Col), Cells(i + 2 + j, Email3Col)).ClearContents
                Cells(i + 2 + j, Email1Col) = SplEmail3
            Next j
        End If
        Range(Cells(i, Email2Col), Cells(i, Email3Col)).ClearContents
    Else
        Rows(i).EntireRow.Delete
    End If
Skip:
Next i

sample data:

col1, col2,..., col6, col7 ,  col8
name, bla, ...,mail1,mail2,(mail3,mail4,mail5)

needs to become this:

col1, col2,..., col6
name, bla, ...,mail1

原文:https://stackoverflow.com/questions/38674587
更新时间:2023-04-28 16:04

最满意答案

问题是你的search-box div有一个固定的高度,你的result div有position: absolute; 这会阻止你的card生长。

绝对定位的元素不计入文档流的一部分,因此它们的宽度和高度不会影响其父项的维度。

只需改变position: absolute; position:relative; 将解决您的问题。

有问题的股利。


The problem is your search-box div has a fixed height and your result div has position: absolute; which prevents your card div to grow.

Absolutely positioned elements are not counted as part of document flow, so their width and height won't affect the dimensions of their parents.

Simply change the position: absolute; to position:relative; will fix your problem.

The problematic div.

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