Unicode字符的名称(Unicode character by name)
在julia 0.6中有可能通过其名称获得unicode字符吗?
在python中,这是可能的
s = u'\N{SECTION SIGN}'
有类似的东西吗? 我知道我能做到
s = '\u00a3'
但我想通过名字来做。
谢谢
It is possible in julia 0.6 obtain the unicode character by its name?
In python it is possible by doing
s = u'\N{SECTION SIGN}'
There is something alike? I know I can do
s = '\u00a3'
but I want to do it by name.
Thank you
原文:https://stackoverflow.com/questions/50292149
最满意答案
如果我没有误解,逻辑图中多对多的游戏 - 开发者关系,那么它应该是[游戏] -1:N- [赋值] -N:1- [开发人员]这里的分配是你的“developer_games”表,我建议你重命名表方便
根据您的场景,CakePHP中推荐的实现将是3个模型类。
<?php class Developer extends AppModel { var $name = 'Developer'; var $hasMany = array('Assignment'); } ?> <?php class Game extends AppModel { var $name = 'Game'; var $hasMany = array('Assignment'); } ?> <?php class Assignment extends AppModel { var $name = 'Assignment'; var $belongsTo = array('Game','Developer'); } ?>
这是添加新分配的代码
//retrieved submitted data --> $data $data = $this->data; // this is for the case you want to insert into 3 tables at a same time $newGame = $this->Game->create(); $newGame = array( 'Game'=> array( 'name' => $data['Game']['name'] ) ); $this->Game->save($newGame); $newGameId = $this->Game->getLastInsertId(); $newDev = $this->Developer->create(); $newDev = array( 'Developer'=> array( 'name' => $data['Developer']['name'] ) ); $this->Developer->save($newDev); $newDevId = $this->Developer->getLastInsertId(); /** * or if you already have Game Id, and Developer Id, then just load it on, and * put it in the statement below, to create a new Assignment **/ $newAssignment = $this->Assignment->create(); $newAssignment = array( 'Assignment' => array( 'game_id' => $newGameId, 'developer_id' => $newDevId, ) ); $this->Assignment->save($newAssignment);
If I dont misunderstood, Game-Developer relationships in many-to-many in logical diagram, then it should be [Game]-1:N-[Assignment]-N:1-[Developer] Assignment here is your "developer_games" table, I suggest you rename the table for convenient
According to your scenario, recommended implementation in CakePHP would be 3 model classes.
<?php class Developer extends AppModel { var $name = 'Developer'; var $hasMany = array('Assignment'); } ?> <?php class Game extends AppModel { var $name = 'Game'; var $hasMany = array('Assignment'); } ?> <?php class Assignment extends AppModel { var $name = 'Assignment'; var $belongsTo = array('Game','Developer'); } ?>
Here is the code to add new Assignment
//retrieved submitted data --> $data $data = $this->data; // this is for the case you want to insert into 3 tables at a same time $newGame = $this->Game->create(); $newGame = array( 'Game'=> array( 'name' => $data['Game']['name'] ) ); $this->Game->save($newGame); $newGameId = $this->Game->getLastInsertId(); $newDev = $this->Developer->create(); $newDev = array( 'Developer'=> array( 'name' => $data['Developer']['name'] ) ); $this->Developer->save($newDev); $newDevId = $this->Developer->getLastInsertId(); /** * or if you already have Game Id, and Developer Id, then just load it on, and * put it in the statement below, to create a new Assignment **/ $newAssignment = $this->Assignment->create(); $newAssignment = array( 'Assignment' => array( 'game_id' => $newGameId, 'developer_id' => $newDevId, ) ); $this->Assignment->save($newAssignment);
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