首页 \ 问答 \ TYPO3计算具有约束的对象并在流体模板中显示结果(TYPO3 count objects with constraint and display result in fluid template)

TYPO3计算具有约束的对象并在流体模板中显示结果(TYPO3 count objects with constraint and display result in fluid template)

 我已经使用扩展构建器构建了一个扩展来处理objects ，一个object可以是“项目”或“项目”。  
 一个对象的字段status有4个选项，并用一个整数填充（3 =已售出）。  
 对象可以被签名为“项目”，在这种情况下，它具有用于isproject的布尔值1和具有相关对象作为项的字段项。  
 这一切都运行正常，我可以使用我的流体模板迭代项目，并使用<f:count>{object.items}</f:count>显示项目所属的项目数。  
 以同样的方式，我应该只显示已售商品的数量 ...... 
 （ <f:count where="object.items.status == 3">{object.items}</f:count>这显然不起作用，只是为了呈现这个想法）  
 使用<f:debug>{object}</f:debug>我看到为所有项目定义的字段status ... 
 因为我不知道如何解决这个问题，所以我可能遗漏了一些重要的信息 

I have build an extension with the extension builder that handles objects, an object can be an "item" or a "project". 
An object has a field status which has 4 options, and is filled with an integer (3 = sold). 
An object can be signed as a "project", in that case it has a boolean 1 for isproject and a field items with related objects as items. 
this all works fine, I can iterate trough the projects with my fluid template and with <f:count>{object.items}</f:count> display the number of items appartaining to the project. 
In the same fashion I should display the count of only the sold items ...
 (<f:count where="object.items.status == 3">{object.items}</f:count> this obviously does not work, just to render the idea) 
with <f:debug>{object}</f:debug> I see the field status defined for all items ...
 since I have no idea how to approch this I might have left out some vital information

原文：https://stackoverflow.com/questions/41799848

更新时间：2022-12-22 06:12

最满意答案

 您可以使用for和pattern匹配其返回值：  
map = %{
  drop_off_lat: nil,
  drop_off_lng: "4.5",
  pick_up_lat: "6.5e2",
  pick_up_lng: nil,
}


[drop_off_lat, drop_off_lng, pick_up_lat, pick_up_lng] =
  for key <- [:drop_off_lat, :drop_off_lng, :pick_up_lat, :pick_up_lng] do
    case map[key] do
      nil -> 0.0
      value -> String.to_float(value)
    end
  end

IO.inspect {drop_off_lat, drop_off_lng, pick_up_lat, pick_up_lng}
 
 输出：  
{0.0, 4.5, 650.0, 0.0}

You can use for and pattern match its return value: 
map = %{
  drop_off_lat: nil,
  drop_off_lng: "4.5",
  pick_up_lat: "6.5e2",
  pick_up_lng: nil,
}


[drop_off_lat, drop_off_lng, pick_up_lat, pick_up_lng] =
  for key <- [:drop_off_lat, :drop_off_lng, :pick_up_lat, :pick_up_lng] do
    case map[key] do
      nil -> 0.0
      value -> String.to_float(value)
    end
  end

IO.inspect {drop_off_lat, drop_off_lng, pick_up_lat, pick_up_lng}
 
Output: 
{0.0, 4.5, 650.0, 0.0}

TYPO3计算具有约束的对象并在流体模板中显示结果(TYPO3 count objects with constraint and display result in fluid template)

最满意答案

相关问答

迭代地图上的所有键(Iterating over all the keys of a map)[2023-07-12]

必须包含所有可能的密钥的地图？(Map which must contain all possible keys?)[2022-02-24]

如何迭代地图键和值？(How to Iterate Over Map Keys and Values?)[2021-10-22]

使用多个键更新嵌套地图(Updating nested map with multiple keys)[2022-05-03]

有两个键的地图[重复](A map with two keys [duplicate])[2023-06-03]

查找地图是否包含多个键(Find if a map contains multiple keys)[2022-10-18]

具有多个键的Java地图(Java Map with multiple keys)[2021-09-05]

当插入/删除由其他线程在地图上进行时迭代地图键(Iterate map keys while insert/remove is going on the map by other threads)[2024-02-03]

在地图上迭代多个键(Iterate through multiple keys on map)[2021-11-19]

查找多个键是否映射到相同的值(Finding if Multiple Keys Map to the Same Value)[2022-01-20]

相关文章

最新问答