首页 \ 问答 \ 拖放后更新Image的位置(Update position of Image after drag and drop)

拖放后更新Image的位置(Update position of Image after drag and drop)

我在我的一些图像上实现了拖放功能。 除了图像的新位置没有保存并且每次重新启动应用程序时它们最终都在左下角,它的效果很好。 这就是我做的:

public GameScreen()  {
stageImage = new Stage();
@Override
public void render(float delta) {
game.batch.setProjectionMatrix(camera.combined);

    camera.update();


    game.batch.begin();
flowerImage.setSize(300, 300);
stageMove.act(Gdx.graphics.getDeltaTime());
    stageMove.draw();
}
 @Override
public void show() {
flowerImage.addListener(new DragListener() {
        public void drag(InputEvent event, float x, float y, int pointer) {
            flowerImage.moveBy(x - flowerImage.getWidth() / 2, y - flowerImage.getHeight() / 2);
            flowerImage.setPosition(x,y);

        }
    });
stageMove.addActor(flowerImage);
btnArrow.addListener(new ChangeListener() {

                @Override
                public void changed(ChangeEvent event, Actor actor) {
stageMove.clear();
game.setScreen(0);

退出屏幕时我必须.clear()阶段,否则当我重新进入时,舞台将创建图像的副本。 那么有人有解决方案吗? 我尝试过只是扮演舞台并从它的源头绘制图像,但这具有相同的效果。


I´ve implemented a drag and drop function on some of my images. And it works great besides that the new position of the images isn´t saved and they end up in the bottom left corner each time I restart the app. This is how I´ve done:

public GameScreen()  {
stageImage = new Stage();
@Override
public void render(float delta) {
game.batch.setProjectionMatrix(camera.combined);

    camera.update();


    game.batch.begin();
flowerImage.setSize(300, 300);
stageMove.act(Gdx.graphics.getDeltaTime());
    stageMove.draw();
}
 @Override
public void show() {
flowerImage.addListener(new DragListener() {
        public void drag(InputEvent event, float x, float y, int pointer) {
            flowerImage.moveBy(x - flowerImage.getWidth() / 2, y - flowerImage.getHeight() / 2);
            flowerImage.setPosition(x,y);

        }
    });
stageMove.addActor(flowerImage);
btnArrow.addListener(new ChangeListener() {

                @Override
                public void changed(ChangeEvent event, Actor actor) {
stageMove.clear();
game.setScreen(0);

I have to .clear() the stage when exiting the screen, otherwise the stage will create a duplicate of the image when I re-enter. So does anyone have a solution to this? I tried just acting the stage and drawing the image from it´s source, but that has the same effect.


原文:https://stackoverflow.com/questions/30030132
更新时间:2021-09-25 21:09

最满意答案

使用网络地图为您的操作系统(在Windows中,右键单击资源管理器和Map Network Drive的共享文件夹)。 然后,您可以使用映射驱动器从SQL Developer运行该脚本,例如: @z:\Shares\test\execute_report.sql

您可以对spool和output文件使用相同的文件寻址


Use network map for your operating system (in Windows, right click the shared folder in explorer and Map Network Drive). Then you can run the script from SQL Developer using the mapped drive, for example: @z:\Shares\test\execute_report.sql

You can use the same addressing of file for spool and output file

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