首页 \ 问答 \ 使用Thinking Sphinx搜索索引模型对象的集合(Searching through a collection of indexed model objects using Thinking Sphinx)

使用Thinking Sphinx搜索索引模型对象的集合(Searching through a collection of indexed model objects using Thinking Sphinx)

我有一个属于用户的技术模型,由Thinking Sphinx索引。

我的模型中还有一个方法返回一个Technique对象数组:

def possible_children(user)
    user.techniques - (self.children + [self])
end

这只是采用用户拥有的技术,减去已经是'self'技术对象的子项的技术,以及'self'本身,并返回剩余的技术对象。

然后在控制器中我实例化一组可能的孩子,如下所示:

 @possible_children = @technique.possible_children(current_user).search params[:search]

这将返回“未定义的方法'搜索'#”

不确定这是否相关,但发生的控制器不是TechniquesController。

我想要做的是搜索由Model方法返回的任意集合。

有任何想法吗?

如果我需要提供更多信息,请告诉我。 谢谢。


I have a Technique model which belongs_to User and is indexed by Thinking Sphinx.

I also have a method in my model that returns an array of Technique objects:

def possible_children(user)
    user.techniques - (self.children + [self])
end

This just takes the techniques that a user has, subtracts out those of the techniques that are already the children of the 'self' technique object, along with 'self' itself, and returns the remaining technique objects.

Then in a controller I instantiate a collection of possible children like so:

 @possible_children = @technique.possible_children(current_user).search params[:search]

This returns an "undefined method 'search' for #"

Not sure if this is relevant but the controller this takes place in is not the TechniquesController.

What I am trying to do is search an arbitrary collection returned by a Model method.

Any ideas?

Let me know if I need to provide more information. Thank you.


原文:https://stackoverflow.com/questions/6591054
更新时间:2021-09-19 10:09

最满意答案

我认为你应该绘制箭头作为依赖箭头走向另一个方向。 这有助于以这种方式思考,因为执行路径是由require方法确定的。 在你的场景中,它非常简单,因为你只有一个具有条件依赖性的TaskA。

您只需要在开始时添加一个任务,这取决于两个TaskB和一个指示任务b是否在样本上运行的指示器

伪代码:

ParentTask
  def requires():
     return [TaskB(sample_type=True), 
             TaskB(sample_type=False)]

TaskB
  def requires():
    return TaskA(sample_type)

TaskA
  def requires():
    if sample_type:
      return SampleTask()
    else:
      return CleanTask()

SampleTask
  def requires():
    return CleanTask()

CleanTask
  def requires()
    return CollectData()

I think you should draw the arrows as dependency arrows going the other way. It helps to think about it this way since the execution path is determined by the requires methods. In your scenario, it is very simple because you just have a TaskA that has a conditional dependency.

You just need to add one more task at the start that depends on two TaskBs and an indicator of whether the taskb is to be run on the sample

Pseudocode:

ParentTask
  def requires():
     return [TaskB(sample_type=True), 
             TaskB(sample_type=False)]

TaskB
  def requires():
    return TaskA(sample_type)

TaskA
  def requires():
    if sample_type:
      return SampleTask()
    else:
      return CleanTask()

SampleTask
  def requires():
    return CleanTask()

CleanTask
  def requires()
    return CollectData()

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