我将我的脚本条带化为以下内容： 
 
search() {
    grep foobar ~/!(test1|test2)
}
 
 非常直截了当。 我想创建一个grep文本foobar的过程，但不要在test1或test2文件夹中grep 
 
 如果我只是在bash命令行中运行它，它按预期工作（！）。 程序已创建并可以调用： 
 
boyang@vbox-ubuntu:~$ search
grep: /home/boyang/Code/analytics.jpg: Is a directory
/home/boyang/Code/bash_includes:    grep foobar ~/Code/!(test1|test2)
 
 如果我把它放在脚本中（例如bash_includes ），并在.bashrc中获取它： 
 
if [ -f ~/bash_includes ]; then
    . ~/bash_includes
fi
 
 它给： 
 
bash: /home/boyang/bash_includes: line 2: syntax error near unexpected token `('
bash: /home/boyang/bash_includes: line 2: `    grep foobar ~/!(test1|test2)'
 
 我尝试添加shebang，尝试添加引号（ "~/!(test1|test2)"或'~/!(test1|test2)'或\`~/!(test1|test2)\` ）。 什么都行不通 
 
 我不是一个bash专家，但这是令人费解的。 我错过了什么？ 
 
 Ubuntu 14.04 Bash 4.3.11（1） - 发布 

I stripe down my script to the following:
 
search() {
    grep foobar ~/!(test1|test2)
}
 
Very straight forward. I want to create a procedure that grep text foobar, but don't grep in test1 or test2 folder
 
If I simply run this in bash command line, it works as expected(!). Procedure is created and can be called:
 
boyang@vbox-ubuntu:~$ search
grep: /home/boyang/Code/analytics.jpg: Is a directory
/home/boyang/Code/bash_includes:    grep foobar ~/Code/!(test1|test2)
 
If I put this in a script (e.g. bash_includes), and source it in .bashrc:
 
if [ -f ~/bash_includes ]; then
    . ~/bash_includes
fi
 
it gives:
 
bash: /home/boyang/bash_includes: line 2: syntax error near unexpected token `('
bash: /home/boyang/bash_includes: line 2: `    grep foobar ~/!(test1|test2)'
 
I tried adding shebang, tried adding quotes ("~/!(test1|test2)" or '~/!(test1|test2)' or \`~/!(test1|test2)\`). Nothing works
 
I'm not a bash expert, but this is puzzling. What am I missing?
 
Ubuntu 14.04 Bash 4.3.11(1)-release

原文：https://stackoverflow.com/questions/40003892