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搜索并替换linux中所有文件中的代码块(search and replace block of code in all files in linux)

这个问题在哲学上类似于这里一次又一次出现的问题:

但是他们(除了最后一个)都处理简单的替换。 我有一个很大的代码块出现在许多文件中(我希望复制/粘贴源代码可以通过法律惩罚),我需要替换它。

有什么能帮到我的吗? 我想避免“sed”if the block(就像在上面的第三个类似问题中所做的那样),因为这将花费一天的大部分时间。 如果我必须暂时安装一些特定的文本编辑器,那就这样吧。


This question is philosophically similar to a question that's come up time and time again here:

But they (with the exception of the last one) all deal with simple replacements. I have a somewhat large block of code which appears in many files (I wish copy/pasting source code was punishable by law), and I need to replace it.

Is there anything that will help me out here? I want to avoid "sed"ifying the block (as is done in the third similar question above) because that will take the better part of a day. If I have to temporarily install some particular text editor, so be it.


原文:https://stackoverflow.com/questions/10557379
更新时间:2023-10-16 13:10

最满意答案

根据Play提供的文档 ,您可以在应用程序启动时使用http.port参数来指定要侦听的端口。 绑定到端口80(标准HTTP端口)将允许您通过域名单独访问您的应用程序:

-Dhttp.port=80

请注意,从2.1版开始,可以将Play应用程序配置为通过HTTPS提供内容。 在这种情况下,您可以使用类似的https.port参数并绑定到端口443(标准HTTPS端口):

-Dhttps.port=443

As per the documentation provided by Play, you can use the http.port argument on application startup to specify which port to listen on. Binding to port 80 (the standard HTTP port) will allow you to get to your application via domain name alone:

-Dhttp.port=80

Note that as of version 2.1, Play applications can be configured to serve content over HTTPS. In this case you can use the similar https.port argument and bind to port 443 (the standard HTTPS port):

-Dhttps.port=443

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