SQL Query返回始终具有相同值的记录(SQL Query returning records that have always the same value)
我正在学习SQL并做一些练习。 我不能给你确切的场景,因为我正在练习的网站不希望任何解决方案直接在网上找到,所以我会用其他的话来解释这种情况。 我遇到的问题是使用带有X,Y和Z列的XYZ表。列X可以有重复项,列Z也可以。 我需要找到的是在Z中总是具有相同值的X.所以
X Y Z 1 ? a 1 ? a 2 ? b 2 ? c 3 ? c 3 ? a会让我回归1,因为当X是1时,Z总是a。
我真正的问题是我觉得我缺少一些SQL知识才能实现这一目标。 我很感激,如果有人能给我一个提示,而不是一个解决方案,但可能是我缺少的SQL知识的链接,或者可以让我这样做的SQL语句的简要说明。
否则祝你有个愉快的一天。 大卫。
编辑:SELECT X FROM XYZ GROUP BY X HAVING COUNT(DISTINCT Z)= 1工作,我理解得很好。 现在我无法理解的是如何将Z列添加到结果集中。
I am learning SQL and doing some practice. I cannot give you the exact scenario because the website I'm practicing on don't want any solution to be found directly on the web so I'll explain the situation in other words. The question I am stuck is using a table XYZ with columns X, Y, and Z. Column X can have duplicates and column Z also. what I need to find is the X's that always have the same value in Z. So
X Y Z 1 ? a 1 ? a 2 ? b 2 ? c 3 ? c 3 ? awould return me 1 because when X is 1 Z is always a.
My real problem is that I feel I am missing some SQL knowledge in order to achiev this. I would appreciate it if anyone can give me a hint, not a solution but maybe a link to the the SQL knowledge im missing or and brief explanation of the SQL statement that could make me do this.
Otherwise have a nice day. David.
edit: SELECT X FROM XYZ GROUP BY X HAVING COUNT(DISTINCT Z) = 1 worked and I understand it well. Now what I cannot understand is how to add the Z column to the resultset.
原文:https://stackoverflow.com/questions/21195631
最满意答案
正如我看到你在现代工具包中 。 因此,您需要首先找到适合的列表, 文档
listeners: { selectionchange : function(tree, rec) { if (rec.data.text === 'University') { //Call the tab from here } } },
您的代码已更新:
items: [{ region: 'west', width: 200, reference: 'treelistContainer', layout: { type: 'vbox', align: 'stretch' }, itemId:'addNewTab', border: true, scrollable: 'y', bufferedRenderer: false, animate: true, rootVisible: false, items: [{ xtype: 'treelist', reference: 'treelist', itemId:'childpanel', listeners: { selectionchange : function(tree, rec) { if (rec.data.text === 'University') { //Call the tab from here } } }, store: { root: { expanded: true, children: [{ text: 'Home', iconCls: 'x-fa fa-home', children: [{ text: 'Messages', iconCls: 'x-fa fa-inbox', leaf: true }] }, { text: 'Users', iconCls: 'x-fa fa-user', children: [{ text: 'Tagged', iconCls: 'x-fa fa-tag', leaf: true }, { text: 'Inactive', iconCls: 'x-fa fa-trash', leaf: true }] }, { text: 'Groups', iconCls: 'x-fa fa-group', leaf: true }, { text: 'Settings', iconCls: 'x-fa fa-wrench', children: [{ name:'haseeb', text: 'University', iconCls: 'x-fa fa-university', leaf: true, itemId: 'bar2', // cls='mycls' }] }] } },},}],
As I saw you are in Modern Toolkit. So you need first to find the right listener for treelist, documentation
listeners: { selectionchange : function(tree, rec) { if (rec.data.text === 'University') { //Call the tab from here } } },
Your code updated:
items: [{ region: 'west', width: 200, reference: 'treelistContainer', layout: { type: 'vbox', align: 'stretch' }, itemId:'addNewTab', border: true, scrollable: 'y', bufferedRenderer: false, animate: true, rootVisible: false, items: [{ xtype: 'treelist', reference: 'treelist', itemId:'childpanel', listeners: { selectionchange : function(tree, rec) { if (rec.data.text === 'University') { //Call the tab from here } } }, store: { root: { expanded: true, children: [{ text: 'Home', iconCls: 'x-fa fa-home', children: [{ text: 'Messages', iconCls: 'x-fa fa-inbox', leaf: true }] }, { text: 'Users', iconCls: 'x-fa fa-user', children: [{ text: 'Tagged', iconCls: 'x-fa fa-tag', leaf: true }, { text: 'Inactive', iconCls: 'x-fa fa-trash', leaf: true }] }, { text: 'Groups', iconCls: 'x-fa fa-group', leaf: true }, { text: 'Settings', iconCls: 'x-fa fa-wrench', children: [{ name:'haseeb', text: 'University', iconCls: 'x-fa fa-university', leaf: true, itemId: 'bar2', // cls='mycls' }] }] } },},}],
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