我如何让它四舍五入,而不是总是倒圆角?(How do I make it round off instead of always round down?)
这是我的公式:
int a; int b; int c; double multiplier; amount = Convert.ToInt32(Math.Round(multiplier * a * (4 * b + c) / 100, 0));
当我得到一个值使得它有一个小数点以上的值时,它会变成四舍五入。 我该如何做到这一点,以便这个公式能够最终结果(我知道如何显示为一个字符串)?
Here's my formula:
int a; int b; int c; double multiplier; amount = Convert.ToInt32(Math.Round(multiplier * a * (4 * b + c) / 100, 0));
When I get a value that would make it have a decimal of .5 or greater it's rounding down instead. How do I make it so that this equation will round off the final result (and I know how to display as a string)?
原文:https://stackoverflow.com/questions/20981177
更新时间:2023-10-24 17:10
最满意答案
最后,我在自定义视图类中创建了一个函数,其中ListView和行数作为参数。 在视图中我将setOnScrollListener设置为ListView,并在滚动到自定义视图的全局滚动变量时指定ListView的位置。 喜欢这个
public void setListView(final TwoWayView listView, int totalListRows) { totalColumns = totalListRows; for (int i = 0; i < totalColumns; i++) { listViewItemHeights.put(i, (int) getResources().getDimension(R.dimen.column_width)); } listView.setOnScrollListener(new TwoWayView.OnScrollListener() { @Override public void onScrollStateChanged(TwoWayView view, int scrollState) { } @Override public void onScroll(TwoWayView view, int firstVisibleItem, int visibleItemCount, int totalItemCount) { c = listView.getChildAt(0); if (c != null) { int oldScrollX = scrollX; scrollX = -c.getLeft(); for (int i = 0; i < listView.getFirstVisiblePosition(); ++i) { if (listViewItemHeights.get(i) != null) { scrollX += listViewItemHeights.get(i); } } scrollBy(scrollX - oldScrollX, 0); } } }); }
At the end I created a function in my custom view class with the ListView and the number of rows as parameters. Inside the view I setOnScrollListener to the ListView and I assign the position of my ListView while scrolling to my global scroll variable of the custom view. Like this
public void setListView(final TwoWayView listView, int totalListRows) { totalColumns = totalListRows; for (int i = 0; i < totalColumns; i++) { listViewItemHeights.put(i, (int) getResources().getDimension(R.dimen.column_width)); } listView.setOnScrollListener(new TwoWayView.OnScrollListener() { @Override public void onScrollStateChanged(TwoWayView view, int scrollState) { } @Override public void onScroll(TwoWayView view, int firstVisibleItem, int visibleItemCount, int totalItemCount) { c = listView.getChildAt(0); if (c != null) { int oldScrollX = scrollX; scrollX = -c.getLeft(); for (int i = 0; i < listView.getFirstVisiblePosition(); ++i) { if (listViewItemHeights.get(i) != null) { scrollX += listViewItemHeights.get(i); } } scrollBy(scrollX - oldScrollX, 0); } } }); }
相关问答
更多-
ListView无法滚动(ListView fails to scroll)[2023-10-16]
您的ListView实际上可能非常小,但不会出现这种可见的溢出。 尝试在ListView的样式属性上设置flex: 1或height: 587 。 Your ListView might actually be quite small but not appear that way do to visible overflow. Try setting flex: 1 or height: 587 on your ListView's style property. -
我认为你应该使用不同的方法并存储你点击的项目的位置。 然后,当您创建视图时,检查位置是否已存储并更改背景。 希望它能帮到你 I think you should use a different approach and store somewhere the position of the item you have clicked on. Then when you create the View check if the position is stored and change the backgro ...
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如果您不需要ListView的所有功能,您可能希望使用ScrollView并在某处使用Repeater。 像这样的东西:
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