基于范围的数字猜谜游戏(range based number guessing game)

 我想找到一个范围内两个数字之间的差异，但我需要能够环绕到范围的开头，就像一个循环列表。 
 
 范围是9。 
 
 因此，如果数字为6且猜测为5，则答案应为1，但如果数字为8且猜测为2，则答案应为3。 
 
 我的第一个想法是将数字增加10，如下所示： 
 
n is the correct number, g is the guess, r is the result. 

( let
   [ r (min (- (+ n 10) g) (- g n)) ]

   (if (> 0 r) ( * -1 r ) r) ) 
)
 
 ...并且它适用于环绕，但问题是数字10的存在如果包装则将结果增加1。 只是从结果中减去1或数字在所有情况下都不起作用。 
 
 根据所讨论的数字，结果是否定的，因此if语句是将其交换为正数。 
 
 这不完全是一个clojure问题，它确实是一个数学问题，我在任何语言中都会遇到这个问题，但它恰好就是我正在编写的内容。我刚开始使用clojure（或任何函数）语言），所以我完全可能做错了或非常单一的。 
 
 谢谢你的帮助 

I want to find the difference between two numbers in a range, but I need to be able to wrap around to the beginning of the range, like a circular list.
 
The range is 9.
 
So if the number is 6 and the guess is 5 the answer should be 1, but if the number is 8 and the guess is 2, then the answer should be 3. 
 
My first thought was to bump the number by 10 like this:
 
n is the correct number, g is the guess, r is the result. 

( let
   [ r (min (- (+ n 10) g) (- g n)) ]

   (if (> 0 r) ( * -1 r ) r) ) 
)
 
... and that worked for wrapping around, but then the problem is that the existence of the number 10 increases the result by 1 if it wraps. Just subtracting 1 from the result or the number doesn't work either in all cases. 
 
Depending on the numbers in question, the result is negative, so the if statement is to swap it around to positive. 
 
This isn't a clojure problem exactly, it's really a math issue and I'd have this problem in any language, but it so happens that's what I'm writing it in. I've only just started using clojure (or any functional language), so it's entirely possibly I'm doing things wrong or wildly unidiomatic. 
 
thanks for any help

原文：https://stackoverflow.com/questions/13275704