首页 \ 问答 \ 输入收音机通过按钮，视觉切换行为(input-radios via buttons, visual toggling behavior)

输入收音机通过按钮，视觉切换行为(input-radios via buttons, visual toggling behavior)

 我正在使用下面的代码来模拟带按钮的输入收音机：  
<input id="blah" name="blah" type="hidden" value="true">
<div class="btn-group" data-toggle="buttons-radio">
   <button type=button data-toggle=button class="btn btn-primary" onClick="$('#blah').val(true);">Option1</button>
   <button type=button data-toggle=button class="btn btn-primary" onClick="$('#blah').val(false);">Option2</button>
</div>
 
 它完美的工作，但有一个小问题。 我无法设置默认选项。 如果我将class =“btn btn-primary”更改为class =“btn btn-primary active”（假设选择1（视觉上区分为默认值）），那么按钮的视觉外观切换不再起作用，即一次我点击相反的按钮，他们都保持视觉活跃。  
 问题是可视化的，内部隐藏字段设置正确，没有问题。  
 如何在不中断切换视觉行为的情况下以可视方式制作任何按钮？ 

I'm using the following code to simulate input-radios with buttons : 
<input id="blah" name="blah" type="hidden" value="true">
<div class="btn-group" data-toggle="buttons-radio">
   <button type=button data-toggle=button class="btn btn-primary" onClick="$('#blah').val(true);">Option1</button>
   <button type=button data-toggle=button class="btn btn-primary" onClick="$('#blah').val(false);">Option2</button>
</div>
 
It works perfectly, but there is slight problem. I can not set default Option. If I change class="btn btn-primary" to class="btn btn-primary active" on let say Option1 (to visually distinguish as default), the Toggling of the visual appearance of the buttons don't work any more i.e. once I click the opposite button they both stay visually active. 
The problem is visual, internally the hidden field is set correctly, no problem with that. 
How to make any of the buttons visually-default without breaking toggling visual behavior ?

原文：https://stackoverflow.com/questions/40031636

更新时间：2022-05-13 15:05

最满意答案

 你只能做得稍微好一些。 如果您的C ++ / CLI类包含一些本机资源（通常是使用C ++ / CLI的唯一原因）并且您已正确实现了C ++ / CLI“析构函数”，即~Class1()方法：  
using (var test1 = new Class1()) {
    test1.requirement();
}
 
 这是有效的，因为每个C ++ / CLI类默认实现IDisposable并将~Class1()映射到Dispose的实现。 

You could only do slightly better as you're already doing. If your C++/CLI class contains some native resources (usually the only reason to use C++/CLI) and you've properly implemented the C++/CLI "destructor" i.e. ~Class1() method:  
using (var test1 = new Class1()) {
    test1.requirement();
}
 
This works because each C++/CLI class implements IDisposable by default and maps ~Class1() to an implementation of Dispose.

输入收音机通过按钮，视觉切换行为(input-radios via buttons, visual toggling behavior)

最满意答案

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