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在Scheme中迭代(Iterating in Scheme)

假设我在Scheme中有一个列表列表,如下所示:

 (define a-list  (list (list a b) (list c d) (list e f) (list g h) (list i j)))

我将如何定义一个消耗此列表的函数,以便我可以使用另一个函数来使用列表中的每个字母?

例如,我有另一个功能

(define (smorg a)
  (...))

那么,我怎么去做smorg a,smorg b,smorg c ......?


Let's say that I have a list of lists in Scheme, like so:

 (define a-list  (list (list a b) (list c d) (list e f) (list g h) (list i j)))

How would I go about defining a function that would consume this list such that I could use another function to consume each letter in the list?

For instance, I had another function

(define (smorg a)
  (...))

So, how do I go about doing smorg a, smorg b, smorg c... ?


原文:https://stackoverflow.com/questions/7426987
更新时间:2023-01-31 15:01

最满意答案

您可以通过引用它们的完整路径Kernel.==来管道输入这些运算符(在Kernel中定义) Kernel.==

iex(1)> 0 |> Kernel.==(0)
true
iex(2)> 1 |> Kernel.==(0)
false

You can pipe into such operators (which are defined in Kernel) by referring to their full path, Kernel.==:

iex(1)> 0 |> Kernel.==(0)
true
iex(2)> 1 |> Kernel.==(0)
false

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