首页 \ 问答 \ 与r中缺失或不匹配的组合(combination with missing or mismathes in r)

与r中缺失或不匹配的组合(combination with missing or mismathes in r)

 我必须创造独特的组合，同时允许一些不匹配。 以下是一个例子： 
 

set.seed (1234)
dataf <- data.frame (var1 = sample( c("A", "B", "-"),20, replace = T),
            var2 = sample( c("A"),20, replace = T),
            var3 = sample( c("B", "B", "B", "-"),20, replace = T),
            var4 = sample( c("A","A", "A",  "-"),20, replace = T),
            var5 = sample( c("A", "B", "A", "A", "-"),20, replace = T)
            )
 dataf

 

 规则： 
 

 （1）生成独特的组合： 
 

     A B     A  B  B   - combination 1
    A  A     A  B  B    - combination 2
    B  B     B  A  A    - combination 3 
   so on ...

 

 （2）允许一个（可以是n）不匹配来创建一个类别。 例如： 
 

A   B    A  B  B
A   A    A  B  B
B   A    A  B  B
B   A    B  B  B 
B   A    A  B  A

 

 与不同变量的单一不匹配相同。 
 

 （3）“ - ”表示缺失值，可以被视为与匹配中的整数类似的方式，即允许一个不匹配。 
 

A   B    A  B  B
 A   -    A  B  B
 A   B    A  -  B

 

 但是，如果有两个缺失值，则组合声明为未知（ - ） 
 

 A   B    A  B  B
 A   -    A  -  B
 A   B    A  -  -

 

 以下是针对上述数据的锻炼。 
 

    var1 var2 var3 var4 var5       comb
1     A    A    B    -    -       -

2     B    A    B    A    A        1
3     B    A    B    A    A        1
4     B    A    B    A    A        1
5     -    A    B    A    A        1
6     B    A    B    A    -        1

7     A    A    B    A    B        2
8     A    A    B    A    B        2

9     B    A    B    A    A        1

10    B    A    -    A    -        -

11    -    A    B    A    A        1

12    B    A    B    -    -        -

13    A    A    B    A    A        2

14    -    A    B    -    A        -

15    A    A    B    A    A        2
16    -    A    B    A    A        2
17    A    A    B    A    B        2

18    A    A    -    A    A        3

19    A    A    B    A    B        2

20    A    A    -    A    A        3

 

 任何想法 ？ 

I have to create unique combination while allowing some mismatches. The following is an example:
 

set.seed (1234)
dataf <- data.frame (var1 = sample( c("A", "B", "-"),20, replace = T),
            var2 = sample( c("A"),20, replace = T),
            var3 = sample( c("B", "B", "B", "-"),20, replace = T),
            var4 = sample( c("A","A", "A",  "-"),20, replace = T),
            var5 = sample( c("A", "B", "A", "A", "-"),20, replace = T)
            )
 dataf

 

Rules:
 

(1) Generate Unique combinations:
 

     A B     A  B  B   - combination 1
    A  A     A  B  B    - combination 2
    B  B     B  A  A    - combination 3 
   so on ...

 

(2) Allow one (can be n) mismatch to create a category. For example:
 

A   B    A  B  B
A   A    A  B  B
B   A    A  B  B
B   A    B  B  B 
B   A    A  B  A

 

are same as there a single mismatch at different variables. 
 

(3) "-" indicates missing values, can be treated as similar way as integers in matching means that one mismatch allowed. 
 

A   B    A  B  B
 A   -    A  B  B
 A   B    A  -  B

 

However if there are two missing values then combination is declared unknown (-)
 

 A   B    A  B  B
 A   -    A  -  B
 A   B    A  -  -

 

The following is workout for the above data. 
 

    var1 var2 var3 var4 var5       comb
1     A    A    B    -    -       -

2     B    A    B    A    A        1
3     B    A    B    A    A        1
4     B    A    B    A    A        1
5     -    A    B    A    A        1
6     B    A    B    A    -        1

7     A    A    B    A    B        2
8     A    A    B    A    B        2

9     B    A    B    A    A        1

10    B    A    -    A    -        -

11    -    A    B    A    A        1

12    B    A    B    -    -        -

13    A    A    B    A    A        2

14    -    A    B    -    A        -

15    A    A    B    A    A        2
16    -    A    B    A    A        2
17    A    A    B    A    B        2

18    A    A    -    A    A        3

19    A    A    B    A    B        2

20    A    A    -    A    A        3

 

Any idea ? 

原文：https://stackoverflow.com/questions/12760030
更新时间：2022-01-13 22:01

最满意答案

 要获取包含Python文件的目录的完整路径，请在该文件中写入： 
 

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))

 

 （注意，如果您已经使用os.chdir()来更改当前工作目录，那么上述的咒语将不起作用，因为__file__常量的值相对于当前工作目录而不是由os.chdir()更改os.chdir()调用。） 
 

 

 获取当前工作目录的使用 
 

import os
cwd = os.getcwd()

 

 

 以上使用的模块，常量和功能的文档参考： 
 

     
 
  •  os和os.path模块。 
    •  
 
  •  __file__常数 
    •  
 
  •  os.path.realpath(path) （返回“指定文件名的规范路径，消除路径中遇到的任何符号链接” ） 
    •  
 
  •  os.path.dirname(path) （返回“路径名path的目录名” ） 
    •  
 
  •  os.getcwd() （返回“表示当前工作目录的字符串” ） 
    •  
 
  •  os.chdir(path) （ “将当前工作目录更改为path ” ） 
    •  


To get the full path to the directory a Python file is contained in, write this in that file:
 

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))

 

(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
 

 

To get the current working directory use 
 

import os
cwd = os.getcwd()

 

 

Documentation references for the modules, constants and functions used above:

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