首页 \ 问答 \ 如何将C ++字符串转换为char *?(How to convert a C++ string to a char*? [duplicate])

如何将C ++字符串转换为char *?(How to convert a C++ string to a char*? [duplicate])

可能重复:
将std :: string转换为const char *或char *

简单的问题,但我是C ++的新手。 如何将字符串转换为char * (我从cin读取一个字符串然后我有一个在char[]上运行的函数,所以需要得到一个char * )? 谢谢。


Possible Duplicate:
Convert std::string to const char* or char*

Simple question but I'm new to C++. How do I convert a string to a char * (I read a string from cin then I have a function that operates on char[] so need to get a char *)? Thanks.


原文:https://stackoverflow.com/questions/4394928
更新时间:2023-02-01 18:02

最满意答案

通常, 不建议使用eval

如果输入参数的数量是未知的和变量的,则可以包含varargin作为输入参数,并传递函数句柄而不是函数名称。 varargin将灵活数量的输入参数作为单元数组放在一起,并将它们传递给函数:

function out = anyfun(func_handle, varargin)
out = func_handle(varargin{:})

举个例子:

anyfun(@mod, 123, 100)

ans =

    23

对于您的示例,您应该定义如下函数:

function x_min = minimize(FUNC_handle, x_initial, step_size, varargin)
:
x1 = FUNC_handle(varargin{:});
:

Generally, it is not recommended to use eval.

If the number of input arguments is unknown and variable, you can include varargin as an input argument and pass the function handle instead of the function name. varargin brings a flexible number of input arguments together as a cell array and passes them to the function:

function out = anyfun(func_handle, varargin)
out = func_handle(varargin{:})

As an example:

anyfun(@mod, 123, 100)

ans =

    23

For your example, you should define the function like:

function x_min = minimize(FUNC_handle, x_initial, step_size, varargin)
:
x1 = FUNC_handle(varargin{:});
:

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