首页 \ 问答 \ 使用Ruby和Regular Expression的HAML字符串,创建换行符和制表符(String to HAML using Ruby and Regular Expression, creating newlines and tabs)

使用Ruby和Regular Expression的HAML字符串,创建换行符和制表符(String to HAML using Ruby and Regular Expression, creating newlines and tabs)

我需要知道从以下字符串创建haml的正确语法:

string = "%div.page-title//%h1//<title>/%small <subtitle>"

它需要找到/// ,记住创建缩进的计数。

上面的字符串需要变成:

%div.page-title
  %h1
    <title>
    %small <subtitle>

< >之间不是html,但我要用其他变量替换它们。

我做了一些研究,并看到可能String.scan方法很有用,但我已经尝试了几个小时的东西,我似乎无法弄清楚如何让它工作......


I need to know the correct syntax for creating haml out of the following string:

string = "%div.page-title//%h1//<title>/%small <subtitle>"

It needs to find / & //, remembering the count for creating the indentation.

The above string needs to become:

%div.page-title
  %h1
    <title>
    %small <subtitle>

Between the < > is not html, but I'm going to replace these with other variables..

I did some researching and have seen that probably the String.scan method is useful, but I've been trying stuff for a couple of hours and I can't seem to figure out how to get this to work...


原文:https://stackoverflow.com/questions/15678300
更新时间:2024-04-24 11:04

最满意答案

他们在这里提到了该网站上的JSON API

这是一个REST API。 谷歌为“Java REST客户端”提供了一些如何从Java使用它的例子


They mention JSON API on that site here

It is a REST api. Google for "Java REST client" to get some examples on how to use it from Java

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