首页 \ 问答 \ RoR:通过孩子创建父母(RoR: Create parent through child)

RoR:通过孩子创建父母(RoR: Create parent through child)

我是新手,并且一直在努力解决以下问题。 不幸的是,数小时的搜索还没有找到解决方案,所以我很乐意得到你的意见。

在创建订单时,我尝试创建客户端(作为父级)和订单项(作为子级)。 后者工作正常。 但是,在保存订单时,订单和客户都存储在数据库中,但* client_id *未传递到订单记录。

以下是我的代码:

公司模式

class Company < ActiveRecord::Base

  has_many :orders,     foreign_key: "client_id"
  accepts_nested_attributes_for :orders

  validates :name, 
            :presence => true,
            :uniqueness => { :case_sensitive => false } 

  validates_associated  :users,
                        :orders

  attr_accessible :name, 
                  :account, 
                  :users_attributes,
                  :orders_attributes,  
                  :company_id
end

订单模型

class Order < ActiveRecord::Base

    has_many :order_items
    accepts_nested_attributes_for   :order_items

    belongs_to  :client, class_name: "Company",
                                    foreign_key: "id"
    accepts_nested_attributes_for   :client

    attr_accessible :order_items_attributes,
                    :order_number,
                    :client_attributes,
                    :client_id

    validates_associated    :order_items

    validates_presence_of   :order_number
                            :client_id
end

订单控制器

  def create
    @order = @client.orders.build(params:[orders])
    puts @order.to_yaml

    respond_to do |format|

      if @order.save!
        format.html { redirect_to @order, notice: 'Order was successfully created.' }
        format.json { render json: @order, status: :created, location: @order }
      else
        format.html { render action: "new" }
        format.json { render json: @order.errors, status: :unprocessable_entity }
      end
    end
  end

新订单

<%= simple_form_for @order, :html => { :class => 'form-horizontal' } do |f| %>
    <%= render 'shared/error_messages', :object => @order %> 
  <div class = "span3">
    <%= f.simple_fields_for :client do |client_builder| %>
      <%= client_builder.input  :name, 
                                :label => 'Client' %>
    <% end %>

    <%= f.input :order_number %>
    <%= f.simple_fields_for :order_items do |items_builder| %>
        <%= items_builder.input :reference_number %>
        <%= items_builder.input :item_description %>
    <% end %>

    <%= f.button  :submit,
                  :class => 'btn'%>
    <%= link_to t('.cancel', :default => t("helpers.links.cancel")),
                              orders_path, :class => 'btn' %>
  </div>
<% end %>

感谢您的帮助! 斯特凡


I am new to rails and keep struggling with the following issue. Unfortunately, hours of search have not led to a solution, so I would be more than happy to get your input.

On creating an order, I attempt to create a client (as parent) and order items (as child). The latter works fine. However, on saving the order, both order and client are stored in the database with the exception that the *client_id* is not passed to the order record.

Here follows my code:

Company Model

class Company < ActiveRecord::Base

  has_many :orders,     foreign_key: "client_id"
  accepts_nested_attributes_for :orders

  validates :name, 
            :presence => true,
            :uniqueness => { :case_sensitive => false } 

  validates_associated  :users,
                        :orders

  attr_accessible :name, 
                  :account, 
                  :users_attributes,
                  :orders_attributes,  
                  :company_id
end

Order Model

class Order < ActiveRecord::Base

    has_many :order_items
    accepts_nested_attributes_for   :order_items

    belongs_to  :client, class_name: "Company",
                                    foreign_key: "id"
    accepts_nested_attributes_for   :client

    attr_accessible :order_items_attributes,
                    :order_number,
                    :client_attributes,
                    :client_id

    validates_associated    :order_items

    validates_presence_of   :order_number
                            :client_id
end

Orders Controller

  def create
    @order = @client.orders.build(params:[orders])
    puts @order.to_yaml

    respond_to do |format|

      if @order.save!
        format.html { redirect_to @order, notice: 'Order was successfully created.' }
        format.json { render json: @order, status: :created, location: @order }
      else
        format.html { render action: "new" }
        format.json { render json: @order.errors, status: :unprocessable_entity }
      end
    end
  end

New Order Form

<%= simple_form_for @order, :html => { :class => 'form-horizontal' } do |f| %>
    <%= render 'shared/error_messages', :object => @order %> 
  <div class = "span3">
    <%= f.simple_fields_for :client do |client_builder| %>
      <%= client_builder.input  :name, 
                                :label => 'Client' %>
    <% end %>

    <%= f.input :order_number %>
    <%= f.simple_fields_for :order_items do |items_builder| %>
        <%= items_builder.input :reference_number %>
        <%= items_builder.input :item_description %>
    <% end %>

    <%= f.button  :submit,
                  :class => 'btn'%>
    <%= link_to t('.cancel', :default => t("helpers.links.cancel")),
                              orders_path, :class => 'btn' %>
  </div>
<% end %>

Thanks for your help in advance! Stefan


原文:https://stackoverflow.com/questions/19877012
更新时间:2023-10-23 19:10

最满意答案

问题是当您从数组中删除项目时,数组中其他项的索引向左移动。

假设你在数组中有4个项目( [a, b, c, d] )并且你要移除第一个项目,因此i=0然后第二次迭代中的结果数组将是[b,c,d]i将是i=1现在有效地你在循环中错过了b

var searchresponse = [{
  "items": [{
    "employeeId": "ABC",
    "type": "D",
    "alive": "Yes"

  }, {
    "employeeId": "DEF",
    "type": "D",
    "alive": "Yes"

  }, {
    "employeeId": "NPK",
    "type": "D",
    "alive": "Yes"

  }, {
    "employeeId": "PKN",
    "type": "A",
    "alive": "Yes"
  }],
  "more": false
}];

var data1 = ["ABC", "NPK", "PKN"];

var data1 = ["ABC", "NPK"];
var items = searchresponse[0].items;
for (var i = items.length - 1; i >= 0; i--) {
  if (data1.indexOf(items[i].employeeId) != -1) {
    items.splice(i, 1);
  }
}
console.log(searchresponse[0].items);


The problem is when you remove the item from array, the index of other items in the array shift to the left.

Assume you have 4 items in the array([a, b, c, d]) and you are removing the first item so i=0 then the resulted array in the second iteration will be [b,c,d] and i will be i=1 now effectively you have missed b in the loop

var searchresponse = [{
  "items": [{
    "employeeId": "ABC",
    "type": "D",
    "alive": "Yes"

  }, {
    "employeeId": "DEF",
    "type": "D",
    "alive": "Yes"

  }, {
    "employeeId": "NPK",
    "type": "D",
    "alive": "Yes"

  }, {
    "employeeId": "PKN",
    "type": "A",
    "alive": "Yes"
  }],
  "more": false
}];

var data1 = ["ABC", "NPK", "PKN"];

var data1 = ["ABC", "NPK"];
var items = searchresponse[0].items;
for (var i = items.length - 1; i >= 0; i--) {
  if (data1.indexOf(items[i].employeeId) != -1) {
    items.splice(i, 1);
  }
}
console.log(searchresponse[0].items);

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