R Matrix，获取最小列的索引(R Matrix, get the index of minimum column)

 我是R的新手，我正在学习。 我已经计算了这个区别，就像这样。 （与欧米茄的区别） 
 
final_wights <- apply(wjs,2, function(x) (omega - x))^2 
 
 现在我想获得最小列的列号。 我可以使用最小列值 
 
 col <- apply(final_wights, 2, min) ， 
 
 但我想获得索引，我如何获得矩阵中的索引列号 

I am very new to R, I am learning. I have calculated the difference, column wise like this. (difference with omega)
 
final_wights <- apply(wjs,2, function(x) (omega - x))^2 
 
Now i want to get the column number of the minimum column. I can get minimum column value using 
 
col <- apply(final_wights, 2, min),
 
But i want to get the index of that how do i just get the index column number in the matrix 

原文：https://stackoverflow.com/questions/29666700