首页 \ 问答 \ 如何将varible传递给一个函数到另一个函数并以纯文本形式调用函数并在纯文本中以角js显示值(how to pass the varible into one function to another function and call the fuction in plain text and show the value in the plain text in angular js)

如何将varible传递给一个函数到另一个函数并以纯文本形式调用函数并在纯文本中以角js显示值(how to pass the varible into one function to another function and call the fuction in plain text and show the value in the plain text in angular js)

我在响应中获得十六进制编码值。 我已经为hexc编写代码到ascii但我不知道如何将变量传递给函数并调用函数以在纯文本中显示解码数据。出现错误 - 名称未定义

 <script>
            var app = angular.module('myApp', []);
            app.controller('myCtrl', function ($scope, $http) {
                $http.get('url', {
                    headers: { 'Authorization': 'Basic a2VybmVs==' }
                })
                .then(function (response) {
                    $scope.names = response.data;             

                });
             });
    </script>
    <script>
        function hex_to_ascii(str1) {
            var hex = str1.toString();
            var str = '';
            for (var n = 0; n < hex.length; n += 2) {
                str += String.fromCharCode(parseInt(hex.substr(n, 2), 16));
            }
            return str;
        }
        </script>
<h2>hex_to_ascii(names.hexadata)</h2>

im getting hexadecimal encoded value in the response. i have written code for hexa to ascii but i don't know how to pass the variable to the function and call the function to show decoded data in the plain text.getting error - names undefined

code

 <script>
            var app = angular.module('myApp', []);
            app.controller('myCtrl', function ($scope, $http) {
                $http.get('url', {
                    headers: { 'Authorization': 'Basic a2VybmVs==' }
                })
                .then(function (response) {
                    $scope.names = response.data;             

                });
             });
    </script>
    <script>
        function hex_to_ascii(str1) {
            var hex = str1.toString();
            var str = '';
            for (var n = 0; n < hex.length; n += 2) {
                str += String.fromCharCode(parseInt(hex.substr(n, 2), 16));
            }
            return str;
        }
        </script>
<h2>hex_to_ascii(names.hexadata)</h2>

原文:https://stackoverflow.com/questions/41426204
更新时间:2023-06-09 13:06

最满意答案

好吧,似乎问题出现是因为nls参数。 必须与nls_session(或数据库)_parameters发生冲突。

我不删除这个问题,因为它可能会帮助别人。

如果有人可以详细解释冲突,请回答。 我会接受答案。


Ok, seems that the Problem occurs because of the nls parameters. There must be a conflict with the nls_session(or database)_parameters .

I don't delete the question, because it may will help someone else.

If someone could explain the conflict in detail, pls answer. I will accept the answer.

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