首页 \ 问答 \ react-router createElement和render失败(react-router createElement and render fail)

react-router createElement和render失败(react-router createElement and render fail)

我正在探索react-router并遇到了一个非常基本的问题。 令人沮丧的部分是我在另一个应用程序中使用react-router,它工作正常!!

我在控制台中收到此错误。 我在这里想念的是什么?

警告:React.createElement:type不应为null,undefined,boolean或number。 它应该是一个字符串(对于DOM元素)或一个ReactClass(对于复合组件)。

未捕获的不变违规:元素类型无效:期望一个字符串(对于内置组件)或一个类/函数(对于复合组件)但得到:object。

var React = require('react');
var ReactDOM = require('react-dom');
var Router = require('react-router');
var Route = require('react-router').Route;
var hashHistory = require('react-router').hashHistory;

var App = React.createClass({
  render: function() {
    return <div>App Rendered from React Router!</div>
  }
});

//this works - there is nothing wrong with App component
// ReactDOM.render((
//   <App/>
// ), document.getElementById('app'));


//This works - just so I understand the basics
// var Child = React.createElement('div',{className:'child'});
// var Parent = React.createElement('div',{className:'parent'},Child);
// ReactDOM.render(Parent, document.getElementById('app'));


//this doesn't work - copy pasted from tutorial
ReactDOM.render((
  <Router history={hashHistory}>
    <Route path="/" component={App}/>
  </Router>
), document.getElementById('app'));

//Babel transpiled code
// ReactDOM.render(React.createElement(
//    Router,
//    { history: hashHistory },
//    React.createElement(Route, { path: '/', component: App })
//  ), document.getElementById('app'));


//this doesn't work
// var route = React.createElement(Route, { path: '/', component: App });
// var router = React.createElement(Router,{ history: hashHistory });
//
// ReactDOM.render(router, document.getElementById('app'));

I am exploring react-router and ran into a very basic issue. The frustrating part is I am using react-router in another app and it works fine!!.

I get this error in console. What am I missing here?

Warning: React.createElement: type should not be null, undefined, boolean, or number. It should be a string (for DOM elements) or a ReactClass (for composite components).

Uncaught Invariant Violation: Element type is invalid: expected a string (for built-in components) or a class/function (for composite components) but got: object.

var React = require('react');
var ReactDOM = require('react-dom');
var Router = require('react-router');
var Route = require('react-router').Route;
var hashHistory = require('react-router').hashHistory;

var App = React.createClass({
  render: function() {
    return <div>App Rendered from React Router!</div>
  }
});

//this works - there is nothing wrong with App component
// ReactDOM.render((
//   <App/>
// ), document.getElementById('app'));


//This works - just so I understand the basics
// var Child = React.createElement('div',{className:'child'});
// var Parent = React.createElement('div',{className:'parent'},Child);
// ReactDOM.render(Parent, document.getElementById('app'));


//this doesn't work - copy pasted from tutorial
ReactDOM.render((
  <Router history={hashHistory}>
    <Route path="/" component={App}/>
  </Router>
), document.getElementById('app'));

//Babel transpiled code
// ReactDOM.render(React.createElement(
//    Router,
//    { history: hashHistory },
//    React.createElement(Route, { path: '/', component: App })
//  ), document.getElementById('app'));


//this doesn't work
// var route = React.createElement(Route, { path: '/', component: App });
// var router = React.createElement(Router,{ history: hashHistory });
//
// ReactDOM.render(router, document.getElementById('app'));

原文:https://stackoverflow.com/questions/35916055
更新时间:2022-12-05 22:12

最满意答案

你可以使用Lookahind和Lookahind。 喜欢这个:

System.out.println(Arrays.toString("a;b;c;d".split("(?<=;)")));
System.out.println(Arrays.toString("a;b;c;d".split("(?=;)")));
System.out.println(Arrays.toString("a;b;c;d".split("((?<=;)|(?=;))")));

你会得到:

[a;, b;, c;, d]
[a, ;b, ;c, ;d]
[a, ;, b, ;, c, ;, d]

最后一个是你想要的。

((?<=;)|(?=;))等于之前选择一个空字符; 或之后 。

希望这可以帮助。

编辑 Fabian Steeg对可读性的评论是有效的。 可读性一直是RegEx的问题。 有一件事,我帮助缓解这个是创建一个名称代表正则表达式并使用Java String格式来帮助的变量。 喜欢这个:

static public final String WITH_DELIMITER = "((?<=%1$s)|(?=%1$s))";
...
public void someMethod() {
...
final String[] aEach = "a;b;c;d".split(String.format(WITH_DELIMITER, ";"));
...
}
...

这有一点帮助。 :-D


You can use Lookahead and Lookbehind. Like this:

System.out.println(Arrays.toString("a;b;c;d".split("(?<=;)")));
System.out.println(Arrays.toString("a;b;c;d".split("(?=;)")));
System.out.println(Arrays.toString("a;b;c;d".split("((?<=;)|(?=;))")));

And you will get:

[a;, b;, c;, d]
[a, ;b, ;c, ;d]
[a, ;, b, ;, c, ;, d]

The last one is what you want.

((?<=;)|(?=;)) equals to select an empty character before ; or after ;.

Hope this helps.

EDIT Fabian Steeg comments on Readability is valid. Readability is always the problem for RegEx. One thing, I do to help easing this is to create a variable whose name represent what the regex does and use Java String format to help that. Like this:

static public final String WITH_DELIMITER = "((?<=%1$s)|(?=%1$s))";
...
public void someMethod() {
...
final String[] aEach = "a;b;c;d".split(String.format(WITH_DELIMITER, ";"));
...
}
...

This helps a little bit. :-D

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