Python-忽略特殊字符并仅匹配文本(Python- ignore special characters and match only text)

 我正在尝试检查一个字符串是否存在于列表中： 
 
 我的字符串没有像{，}，\ n，\ n \ n这样的特殊字符 
 
string1='hi'
string2='I'
string3='am new to this'
 
 作为我的列表条目包含像字符串： 
 
list_count="{hi}","\n I","am \n new {to} this\n\n"
 
 我想知道如何通过仅考虑列表的“文本部分”来检查字符串匹配 
 
 注意：我有n个字符串来检查列表 
 
 我已经尝试了下面的代码，似乎没有工作我的目的 
 
 字符串=字符串1，字符串，STRING3 
 
 码： 
 
for i in strings:
    if i in list_count:
        print('yes')
 
 我希望输出结果为是，例如： 
 
if 'hi' in list_count:
 
 它必须通过仅检查文本部分而不包括“{”'}“来打印”是“ 

I am trying to check if a string exists in list:
 
My string is without any special characters like {,},\n,\n\n
 
string1='hi'
string2='I'
string3='am new to this'
 
where as my list entry contains strings like:
 
list_count="{hi}","\n I","am \n new {to} this\n\n"
 
I want to know how can i check for a match of strings by considering only the "text part" of list
 
Note: I am having n number of strings to check in list
 
I have tried below code, seems to not work my purpose
 
strings=string1,string2,string3
 
code:
 
for i in strings:
    if i in list_count:
        print('yes')
 
I want the output to be yes for checks like:
 
if 'hi' in list_count:
 
It has to print yes by only checking for text part and not including '{' '}'

原文：https://stackoverflow.com/questions/50388786