首页 \ 问答 \ PHP MYSQL UPDATE如果存在或INSERT如果没有?(PHP MYSQL UPDATE if Exist or INSERT if not?)

PHP MYSQL UPDATE如果存在或INSERT如果没有?(PHP MYSQL UPDATE if Exist or INSERT if not?)

我不知道这是否远程正确。 我有一个类,我想要更新数据库,如果这些字段当前存在或插入,如果他们没有。 复杂的是我正在加入3个表(set_colors,school_art,baseimage)

任何帮助将是非常好的。

这是我有的:

public function set_layer_colors($value) {
global $db;

$result_array = mysql_query("
IF EXISTS(SELECT * FROM set_colors WHERE school_art_id = '{$value}')

  UPDATE set_colors (school_art_id, baseimage_id, sub_folder, layer)
    SELECT school_art.id, baseimage.id, baseimage.sub_folder, baseimage.layer
    FROM school_art 
    JOIN baseimage ON baseimage.base_folder = school_art.series_code 
    WHERE baseimage.image_type = 'B' ORDER BY school_art.id 

ELSE

 INSERT INTO set_colors (school_art_id, baseimage_id, sub_folder, layer)
    SELECT school_art.id, baseimage.id, baseimage.sub_folder, baseimage.layer
    FROM school_art 
    JOIN baseimage ON baseimage.base_folder = school_art.series_code 
    WHERE baseimage.image_type = 'B' ORDER BY school_art.id 
    ");

return $result_array;

}

提前致谢。


I have no idea if this is even remotely correct. I have a class where I would like to update the database if the fields currently exist or insert if they do not. The complication is that I am doing a joining 3 tables (set_colors, school_art, baseimage)

Any help would be really great.

Here is what I have:

public function set_layer_colors($value) {
global $db;

$result_array = mysql_query("
IF EXISTS(SELECT * FROM set_colors WHERE school_art_id = '{$value}')

  UPDATE set_colors (school_art_id, baseimage_id, sub_folder, layer)
    SELECT school_art.id, baseimage.id, baseimage.sub_folder, baseimage.layer
    FROM school_art 
    JOIN baseimage ON baseimage.base_folder = school_art.series_code 
    WHERE baseimage.image_type = 'B' ORDER BY school_art.id 

ELSE

 INSERT INTO set_colors (school_art_id, baseimage_id, sub_folder, layer)
    SELECT school_art.id, baseimage.id, baseimage.sub_folder, baseimage.layer
    FROM school_art 
    JOIN baseimage ON baseimage.base_folder = school_art.series_code 
    WHERE baseimage.image_type = 'B' ORDER BY school_art.id 
    ");

return $result_array;

}

Thanks in advance.


原文:https://stackoverflow.com/questions/6853190
更新时间:2022-09-19 17:09

最满意答案

好的,我的一位同事弄清楚了:

@Path("somePostEndPoint")
    @POST
    @Produces(value={"application/vnd.api+json",MediaType.APPLICATION_JSON})
    @Consumes(value={"application/vnd.api+json",MediaType.APPLICATION_JSON})

    public Response postService (String someData) {
      //...
    }
  • 不要使用@FormParam ,只需设置一个字符串。 @FormParam需要Content-Type: application/x-www-form-urlencoded

  • 使用@Consumes(value={"application/vnd.api+json",MediaType.APPLICATION_JSON})

这对我们有效。


Ok a colleague of mine figured it out:

@Path("somePostEndPoint")
    @POST
    @Produces(value={"application/vnd.api+json",MediaType.APPLICATION_JSON})
    @Consumes(value={"application/vnd.api+json",MediaType.APPLICATION_JSON})

    public Response postService (String someData) {
      //...
    }
  • Do not use @FormParam, just set a String. @FormParam requires the Content-Type: application/x-www-form-urlencoded

  • use @Consumes(value={"application/vnd.api+json",MediaType.APPLICATION_JSON})

this worked for us.

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