需要OpenGL ES 2.0仿真器(Need OpenGL ES 2.0 Emulator)

 关于指针类型的常量应该“从右到左”读取（并且"const T * buffer" ”实际上意味着“指向const内容的指针”，而不是“指向内容的const指针”，也不是“指向const内容的const指针”）。 
 
 因此，您将使用可变指针到const char缓冲区并将其用于const版本的结构（要求您的const结构具有可变字段 - 这是显示警告的原因）。 如果您打算摆脱警告，您必须移动“const”这样的事情： 
 
void show_string(char * const buffer, const int length) { // <== move const to the right of "*"
    const string_t str = // <== tricky assignment here
        (const string_t) {
        buffer, length
    };
    show_string_internal(str);
}
 
 如果您计划同时拥有const缓冲区，则必须重新定义string_t结构（或作为单独的类型引入）： 
 
typedef struct {
    const uchar_t * buffer; // <== add "const" here
    uint_t length; // excluding null-terminating character
} string_t;
...
void show_string(const char * const buffer, const int length) { // two "const" clauses there
    const string_t str = // <== tricky assignment here
        (const string_t) {
        buffer, length
    };
    show_string_internal(str);
}
 
 希望这可以帮助。 

Constness about pointer types should be read "from right to left" (and "const T * buffer" means "pointer to const content" actually, not "const pointer to content" nor "const pointer to const content).
 
So, you was about to use mutable pointer to const char buffer and use it for const version of structure (asking your const struct having mutable field - this is a reason for the warning shown). In case you plan to get rid of the warning you have to move "const" thing like that:
 
void show_string(char * const buffer, const int length) { // <== move const to the right of "*"
    const string_t str = // <== tricky assignment here
        (const string_t) {
        buffer, length
    };
    show_string_internal(str);
}
 
In case you plan to have const buffer itself as well, you have to redefine your string_t structure (or introduce as separate type):
 
typedef struct {
    const uchar_t * buffer; // <== add "const" here
    uint_t length; // excluding null-terminating character
} string_t;
...
void show_string(const char * const buffer, const int length) { // two "const" clauses there
    const string_t str = // <== tricky assignment here
        (const string_t) {
        buffer, length
    };
    show_string_internal(str);
}
 
Hope this helps.