NHibernate Criteria Query与LINQ to NHibernate(NHibernate Criteria Query vs. LINQ to NHibernate)
我知道有些查询你无法在LINQ to NHibernate中表达你可以使用NHibernate Criteria。 但是,就性能而言,可以安全地假设使用NHibernate Criteria通常比LINQ更好的NHibernate?
I understand that there are queries you can't express in LINQ to NHibernate that you can using NHibernate Criteria. But, as far performance, is it safe to assume that using NHibernate Criteria is generally better than LINQ to NHibernate?
原文:https://stackoverflow.com/questions/2906048
最满意答案
检查tailhead.bat - 它可以显示从某行到另一行的文件内容。如果你有tailHead.bat,你可以:
@echo off ::========================== :: set file=text.txt set "line1=I need only the lines starting from here SOME IMP TEXT" set "line2=I need it till I find this line SOME IMP TEXT" ::======================== for /f "tokens=1 delims=:" %%a in ('findstr /n /c:"%line1%" "%file%"') do set "l1=%%a" for /f "tokens=1 delims=:" %%a in ('findstr /n /c:"%line2%" "%file%"') do set "l2=%%a" ::echo %l1% ::echo %l2% tailhead.bat -file=text.txt -begin=%l1% -end=%l2%
这将包括线。 如果要排除它们,可以使用
set /a
增加开始行并减少结束行Check the tailhead.bat - it can to show a file content from certain line to a another line by number.If you have the tailHead.bat you can:
@echo off ::========================== :: set file=text.txt set "line1=I need only the lines starting from here SOME IMP TEXT" set "line2=I need it till I find this line SOME IMP TEXT" ::======================== for /f "tokens=1 delims=:" %%a in ('findstr /n /c:"%line1%" "%file%"') do set "l1=%%a" for /f "tokens=1 delims=:" %%a in ('findstr /n /c:"%line2%" "%file%"') do set "l2=%%a" ::echo %l1% ::echo %l2% tailhead.bat -file=text.txt -begin=%l1% -end=%l2%
this will include the lines. if you want to exclude them you can increase the begin line and decrease the end line with
set /a
相关问答
更多-
这应该对你有用 - 简而言之,它读取文件的所有行,然后只将包含其中某些内容的行写回到文件中。 $friends = Get-Content friends.txt $friends | Where-Object { $_ } | Set-Content friends.txt This should work for you - in short, it reads all the lines of the file, then writes back only the lines with someth ...
-
SED: sed '5!d' file AWK: awk 'NR==5' file sed: sed '5!d' file awk: awk 'NR==5' file
-
要从input.txt中删除someString出现在第10列中的所有行: findstr /rvc:"^.........someString" input.txt >output.txt /r强制进行正则表达式解释 /v返回不匹配的行 /c:"..."指定正则表达式搜索字符串 ^在行的开头锚定搜索 .........匹配任何9个字符 To delete all lines from input.txt where someString appears in column 10: findstr /rv ...
-
检查tailhead.bat - 它可以显示从某行到另一行的文件内容。如果你有tailHead.bat,你可以: @echo off ::========================== :: set file=text.txt set "line1=I need only the lines starting from here SOME IMP TEXT" set "line2=I need it till I find this line SOME IMP TEXT" ::=========== ...
-
findstr /v /b /L /c:"%username% " users.dat>tempfile.dat move /y tempfile.dat users.dat >nul 应该根据需要删除该行。 findstr查找所有行/v不在/b开头的行/L实际上是/c:"..."包含此字符串。 请注意,对于要删除的字符串,我故意添加了一个空格。 这意味着如果你有用户Fred和Fred Two那么删除Fred不会影响Fred Two记录。 findstr /v /b /L /c:"%username% " ...
-
你没有在第二个链接上学习答案 - 它有一个非常好的解决方案。 我更喜欢使用*]=替换而不是substring的那种技术的变体: @echo off setlocal enableextensions disabledelayedexpansion set "search=
" set "replace=XYZ" set "textFile=C:\abc.txt" for /f "delims=" %%i in ('type "%textFile%" ^| find /v /n "" ^& b ... -
我如何在文本文件中找到重复的行(不包括大小写)并打印出来?(How can I find duplicate lines in a text file and print them? [closed])[2023-06-10]
一个集合很容易: with open('file') as f: seen = set() for line in f: line_lower = line.lower() if line_lower in seen: print(line) else: seen.add(line_lower) This is pretty easy with a set: with open('file') ... -
如何在文本文件中找到一行(How to find a line in a text file)[2022-04-06]
读取.txt文件并将其显示到批处理文件。 使用type命令。 在你的案例中type %talk% 在下面编辑(小)你的代码。 @echo off echo Hello! echo Talk To Me! pause>nul :1 cls echo Enter text set /p talk= if exist %~dp0%talk%.txt ( type %talk%.txt pause>nul goto 1 ) else ( goto dontknow ) : ... -
选项1,使用findstr字符串编号 for %%a in (*.log) do ( for /f "tokens=1,* delims=:" %%b in ( 'findstr /n "^" "%%a" ^| findstr /b "30:"' ) do ( echo(%%c>"%%a" ) ) 选项2,用于命令跳过行 setlocal disabledelayedexpansion for %%a in (*.log) do ( set ...
-
FINDSTR本身应该是一个很好的解决方案。 阅读文档,人们会认为以下文字搜索应该有效。 findstr /vlxg:"temp2.txt" "temp1.txt" >temp.txt 但是下面的FINDSTR错误和限制阻止了上述内容的可靠性 指定多个文字搜索字符串可能无法找到所有匹配项 (bug) 文字搜索可能需要\和/或"作为\\和\"进行转义 解决方案是进行正则表达式搜索。 但这要求必须转义temp2.txt中的正则表达式元字符。 这是我的JREPL.BAT正则表达式查找/替换实用程序的完美任务。 ...