首页 \ 问答 \ NetworkStream截断我的数据?(NetworkStream truncates my data?)

NetworkStream截断我的数据?(NetworkStream truncates my data?)

在同一台电脑上,我有2个控制台应用程序。 (客户端发送文件到服务器)

在我开始之前,我只想提一下,我正在使用这2个async函数:

NetworkStream读取:

 public static Task<int> ReadAsync1(this NetworkStream networkStream, byte[] buffer, int offset, int size)
   {
     return Task<int>.Factory.FromAsync(networkStream.BeginRead, networkStream.EndRead, buffer, offset, buffer.Length, networkStream);
   }

为了写入NetworkStream

   public static Task WriteAsync1(this NetworkStream networkStream, byte[] buffer, int offset, int size)
    {
      return Task.Factory.FromAsync(networkStream.BeginWrite, networkStream.EndWrite, buffer, offset, buffer.Length, networkStream);
    }

我的客户代码

(让我们拿一个简单的文件,我知道它的大小)

在这里输入图像描述

我的代码发送:

 NetworkStream ns = socketForServer.GetStream();
 ns.WriteAsync1(File.ReadAllBytes(@"c:\r\1.jpg"), 0, 1593899);
 ns.Flush();

我的服务器代码 :(阅读...)

byte[] d = new byte[1593899];
networkStream.Read(d, 0, d.Length);
File.WriteAllBytes(@"c:\r\2.jpg",d);

结果:

2.jpg写的是:

在这里输入图像描述

那么问题在哪里?

2.jpg已损坏! 当我尝试打开图像时,我看到:

在这里输入图像描述

(而不是像1.jpg一样的图像)

所以我去看看“十六进制”出了什么问题:

我发现一段时间后 - 它写成零:

更大的图像

在这里输入图像描述

我究竟做错了什么 ? 我该如何修复代码才能发送整个文件?


On the same computer I have 2 console applications. (client sends a file to server)

Before I start I just want to mention that i'm using those 2 async functions :

For reading from NetworkStream:

 public static Task<int> ReadAsync1(this NetworkStream networkStream, byte[] buffer, int offset, int size)
   {
     return Task<int>.Factory.FromAsync(networkStream.BeginRead, networkStream.EndRead, buffer, offset, buffer.Length, networkStream);
   }

For writing to NetworkStream:

   public static Task WriteAsync1(this NetworkStream networkStream, byte[] buffer, int offset, int size)
    {
      return Task.Factory.FromAsync(networkStream.BeginWrite, networkStream.EndWrite, buffer, offset, buffer.Length, networkStream);
    }

My client code :

(let's take a simple file which I know it's size)

enter image description here

My code for sending:

 NetworkStream ns = socketForServer.GetStream();
 ns.WriteAsync1(File.ReadAllBytes(@"c:\r\1.jpg"), 0, 1593899);
 ns.Flush();

My Server code : (reading...)

byte[] d = new byte[1593899];
networkStream.Read(d, 0, d.Length);
File.WriteAllBytes(@"c:\r\2.jpg",d);

Result :

2.jpg is written :

enter image description here

So where is the problem ?

2.jpg is corrupted ! When I try to open the image I see this :

enter image description here

(instead of a the same image as 1.jpg)

So I went to see the "HEX" for what is wrong :

I found out that after a while -all it writes are zeros :

larger iamge

enter image description here

Question

What am I doing wrong ? And how can I fix the code so it will send the whole file ?


原文:https://stackoverflow.com/questions/27630028
更新时间:2023-09-02 18:09

最满意答案

如果randomFunction() static

class CAnotherClass
{
public:
    static void randomFunction();
};

然后, 可以使用以下语法在不创建CAnotherClass对象的情况下调用randomFunction()

CAnotherClass::randomFunction();

如果randomFunction() 不是 static

class CAnotherClass
{
public:
    void randomFunction();
};

然后, randomFunction()没有创建CAnotherClass对象,则无法调用randomFunction() ,然后必须使用以下语法:

CAnotherClass myInstance;
myInstance.randomFunction();

要么:

CAnotherClass().randomFunction(); // temporary object creation

请注意,如果randomFunction()static ,则上述两种语法也可以使用。

PS:我试着猜测没有源代码的问题是什么....希望这会有所帮助!


If you have randomFunction() being static:

class CAnotherClass
{
public:
    static void randomFunction();
};

Then, randomFunction() can be called without a CAnotherClass object being created, using this syntax:

CAnotherClass::randomFunction();

If you have randomFunction() not being static:

class CAnotherClass
{
public:
    void randomFunction();
};

Then, randomFunction() cannot be called without a CAnotherClass object being created, you then have to use this syntax:

CAnotherClass myInstance;
myInstance.randomFunction();

or:

CAnotherClass().randomFunction(); // temporary object creation

Note that, if randomFunction() is static, the two syntaxes above will also work.

PS: I tried to guess what the problem was without the source code....hope this will help!

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