首页 \ 问答 \ 内容复合组件[复制](Inner content composite component [duplicate])

内容复合组件[复制](Inner content composite component [duplicate])

这个问题在这里已经有了答案:

我有我的复合组件<my:panel/>

<composite:interface>
  <composite:attribute name="header" />
  <composite:attribute name="content" />
</composite:interface>

<composite:implementation>
  <div class="panel panel-default">
    <div class="panel-heading">#{cc.attrs.header}</div>
    <div class="panel-body">
      #{cc.attrs.content}
    </div>
  </div>
</composite:implementation>

我用过:

<my:panel header="My header" content="My content"  />

那么,现在我想添加内容属性中的HTML(一个HTML表格)代码。 我怎么能这样做<my:tag/>作品?

<my:tag header="My header" >
  <table style="width:100%">
    <tr>
      <th>Firstname</th>
      <th>Lastname</th>
      <th>Age</th>
    </tr>
  </table> 
</my:tag>

This question already has an answer here:

I have my composite component <my:panel/> :

<composite:interface>
  <composite:attribute name="header" />
  <composite:attribute name="content" />
</composite:interface>

<composite:implementation>
  <div class="panel panel-default">
    <div class="panel-heading">#{cc.attrs.header}</div>
    <div class="panel-body">
      #{cc.attrs.content}
    </div>
  </div>
</composite:implementation>

And i used:

<my:panel header="My header" content="My content"  />

Well, now i want to add html (a html table e.g.) code in content attribute. How could i do for <my:tag/> works like this?

<my:tag header="My header" >
  <table style="width:100%">
    <tr>
      <th>Firstname</th>
      <th>Lastname</th>
      <th>Age</th>
    </tr>
  </table> 
</my:tag>

原文:https://stackoverflow.com/questions/39863030
更新时间:2022-03-15 09:03

最满意答案

为了更好的参考,请看看::

如何将两个模型组合成一个模型,并使用asp.net MVC razor将其传递给视图

然后在服务器端的表单提交(即进入控制器的操作)保存来自视图的数据,如:: ::

public ActionResult Save(CommonViewModel common)
    {
        var FirstModel = new FirstModel();
        FirstModel = common.FirstModel;
        db.Entry(FirstModel).State = EntityState.Added;

        var SecondModel = new SecondModel();
        SecondModel = common.SecondModel;
        db.Entry(SecondModel).State = EntityState.Added;
        db.SaveChanges();
    }

可能这个答案将有助于您的查询答案。


[HttpPost]

    public ActionResult Edit(CompPeripheral cp, int c_id,int em_id,int asset_id)
    {
        if (ModelState.IsValid)
        {
            cp.Compconfig.c_id = c_id;
            cp.Compconfig.em_id = em_id;
            cp.Compconfig.asset_id = asset_id;
            db.tbl_compconfig.Add(cp.Compconfig);
            db.SaveChanges();
            var id = db.tbl_compconfig.Max(a => a.comp_id);
            cp.Comperipheral.comp_id = id;
            //saving Comp Peripheral in database
            db.tbl_comperipheral.Add(cp.Comperipheral);
            db.SaveChanges();
            return RedirectToAction("Index");
        }

        ViewBag.asset_id = new SelectList(db.tbl_assetm, "asset_id", "asset_name", cp.Compconfig.asset_id);
        ViewBag.em_id = new SelectList(db.tbl_employee, "em_id", "em_fullname", cp.Compconfig.em_id);
        ViewBag.c_id = new SelectList(db.tbl_client, "c_id", "c_name", cp.Compconfig.c_id);
        return View(cp);
    }

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