MySQL JOIN与LEFT JOIN的区别(Difference in MySQL JOIN vs LEFT JOIN)
我有这个跨数据库查询...
SELECT `DM_Server`.`Jobs`.*, `DM_Server`.servers.Description AS server, digital_inventory.params, products.products_id, products.products_pdfupload, customers.customers_firstname, customers.customers_lastname FROM `DM_Server`.`Jobs` INNER JOIN `DM_Server`.servers ON servers.ServerID = Jobs.Jobs_ServerID JOIN `cpod_live`.`digital_inventory` ON digital_inventory.jobname = Jobs.Jobs_Name JOIN `cpod_live`.`products` ON products.products_pdfupload = CONCAT(digital_inventory.jobname, ".pdf") JOIN `cpod_live`.`customers` ON customers.customers_id = products.cID ORDER BY `DM_Server`.`Jobs`.Jobs_StartTime DESC LIMIT 50
它运行良好,直到我让他们
LEFT JOIN
。 我以为没有指定一种类型的连接,它被认为是一个LEFT JOIN
。 不是这样吗?I have this cross-database query...
SELECT `DM_Server`.`Jobs`.*, `DM_Server`.servers.Description AS server, digital_inventory.params, products.products_id, products.products_pdfupload, customers.customers_firstname, customers.customers_lastname FROM `DM_Server`.`Jobs` INNER JOIN `DM_Server`.servers ON servers.ServerID = Jobs.Jobs_ServerID JOIN `cpod_live`.`digital_inventory` ON digital_inventory.jobname = Jobs.Jobs_Name JOIN `cpod_live`.`products` ON products.products_pdfupload = CONCAT(digital_inventory.jobname, ".pdf") JOIN `cpod_live`.`customers` ON customers.customers_id = products.cID ORDER BY `DM_Server`.`Jobs`.Jobs_StartTime DESC LIMIT 50
it runs fine until I make them
LEFT JOIN
s. I thought that by not specifying a type of join it was assumed to be aLEFT JOIN
. Is this not the case?
原文:https://stackoverflow.com/questions/9770366
更新时间:2022-03-17 11:03
最满意答案
var arr=[{ "no": "1", "location": "Acheh Baru", "postcode": "32000", "postOffice": "Sitiawan", "state": "Perak" }, { "no": "2", "location": "Akauntan Negeri", "postcode": "30594", "postOffice": "Ipoh", "state": "Perak" }, { "no": "3", "location": "Alor Kechor", "postcode": "32800", "postOffice": "Parit", "state": "Perak" }]; function findObjectByKey(array, key, value) { for (var i = 0; i < array.length; i++) { if (array[i][key] === value) { return array[i]['location']; } } return null; } var obj = findObjectByKey(arr, 'no', "3"); console.log(obj);
var arr=[{ "no": "1", "location": "Acheh Baru", "postcode": "32000", "postOffice": "Sitiawan", "state": "Perak" }, { "no": "2", "location": "Akauntan Negeri", "postcode": "30594", "postOffice": "Ipoh", "state": "Perak" }, { "no": "3", "location": "Alor Kechor", "postcode": "32800", "postOffice": "Parit", "state": "Perak" }]; function findObjectByKey(array, key, value) { for (var i = 0; i < array.length; i++) { if (array[i][key] === value) { return array[i]['location']; } } return null; } var obj = findObjectByKey(arr, 'no', "3"); console.log(obj);
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