使用matplotlib中的换行符对齐图例标题(Centering a legend title with line breaks in matplotlib)

 我使用以下代码来显示matplotlib的图例标题 ： 
 
import matplotlib.pyplot as plt

# data 
all_x = [10,20,30]
all_y = [[1,3], [1.5,2.9],[3,2]]

# Plot
plt.plot(all_x, all_y)

# Add legend, title and axis labels
plt.legend( [ 'Lag ' + str(lag) for lag in all_x], loc='lower right', title='hello hello hello \n world')
plt.show()
 
 
 正如您所看到的，“世界”并非居中。 我希望它居中，我可以通过手动添加空格来实现： 
 
import matplotlib.pyplot as plt

# data 
all_x = [10,20,30]
all_y = [[1,3], [1.5,2.9],[3,2]]

# Plot
plt.plot(all_x, all_y)

# Add legend, title and axis labels
plt.legend( [ 'Lag ' + str(lag) for lag in all_x], loc='lower right', title='hello hello hello \n        world')
plt.show()
 
 
 但这是一个麻烦的解决方案。 
 
 有没有更合适的方法来实现这一目标？ 

I use the following code to display a legend title with matplotlib:
 
import matplotlib.pyplot as plt

# data 
all_x = [10,20,30]
all_y = [[1,3], [1.5,2.9],[3,2]]

# Plot
plt.plot(all_x, all_y)

# Add legend, title and axis labels
plt.legend( [ 'Lag ' + str(lag) for lag in all_x], loc='lower right', title='hello hello hello \n world')
plt.show()
 
 
As you can see, "world" is not centered. I would like it to be centered, I can achieve that by manually adding spaces:
 
import matplotlib.pyplot as plt

# data 
all_x = [10,20,30]
all_y = [[1,3], [1.5,2.9],[3,2]]

# Plot
plt.plot(all_x, all_y)

# Add legend, title and axis labels
plt.legend( [ 'Lag ' + str(lag) for lag in all_x], loc='lower right', title='hello hello hello \n        world')
plt.show()
 
 
but that's a cumbersome solution.
 
Is there any more proper way to achieve that?

原文：https://stackoverflow.com/questions/25356675